Chapter 5: Q 35. (page 429)
Solve the integral:
Short Answer
The required answer is.
Chapter 5: Q 35. (page 429)
Solve the integral:
The required answer is.
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Show that if , then , in the following two ways: (a) by using implicit differentiation, thinking of as a function of , and (b) by thinking of as a function of .
Solve the integral:
Why don’t we need to have a square root involved in order to apply trigonometric substitution with the tangent? In other words, why can we use the substitution when we see , even though we can’t use the substitution unless the integrand involves the square root of? (Hint: Think about domains.)
Complete the square for each quadratic in Exercises 28–33. Then describe the trigonometric substitution that would be appropriate if you were solving an integral that involved that quadratic.
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