Chapter 5: Q 28. (page 429)
Solve the integral:
Short Answer
The required answer is.
Chapter 5: Q 28. (page 429)
Solve the integral:
The required answer is.
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Problem Zero: Read the section and make your own summary of the material.
Why don’t we need to have a square root involved in order to apply trigonometric substitution with the tangent? In other words, why can we use the substitution when we see , even though we can’t use the substitution unless the integrand involves the square root of? (Hint: Think about domains.)
Explain how to know when to use the trigonometric substitutions , Describe the trigonometric identity and the triangle that will be needed in each case. What are the possible values for and in each case?
For each function u(x) in Exercises 9–12, write the differential du in terms of the differential dx.
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