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Each expression that follows is the result of a calculation that uses integration by parts. That is, each is an expression of the form uvvdufor some functions u and v. Identify u, v, du, and dv, and determine the original integral u dv.

-x2cosx+2xcosxdx

Short Answer

Expert verified

u=x2v=-cosxdu=2xdv=sinxudv=x2sinxdx

Step by step solution

01

Step 1. Given information

Integral is-x2cosx+2xcosxdx

02

Step 2. Explanation

Take u=x2,v=-cosx

du=2xdxdv=sinxdxudv=x2sinxdx

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