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Prove that the ratio of successive terms of a nonzero geometric sequence is constant

Short Answer

Expert verified

Proved

Step by step solution

01

Step 1. Given 

Consider the geometric sequenceak=crk

02

Step 2. Proof

The general term of the sequence is ak=crkis ak=crk.

The ratio of two successive terms is ak=crkis:

ak+1ak=crk+1crk=rk+1-k=rThustheratioak+1akisconstant.

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Most popular questions from this chapter

Use either the divergence test or the integral test to determine whether the series in Given Exercises converge or diverge. Explain why the series meets the hypotheses of the test you select.

โˆ‘k=1โˆžโ€Škโˆ’3/2

Prove Theorem 7.25. That is, show that the series โˆ‘k=1โˆžakandโˆ‘k=Mโˆžakeither both converge or both diverge. In addition, show that if โˆ‘k=Mโˆžakconverges to L, thenโˆ‘k=1โˆžakconverges tolocalid="1652718360109" a1+a2+a3+....+aM-1+L.

True/False:

Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: If akโ†’0, then โˆ‘k=1โˆžakconverges.

(b) True or False: If โˆ‘k=1โˆžakconverges, then akโ†’0.

(c) True or False: The improper integral โˆซ1โˆžf(x)dxconverges if and only if the series โˆ‘k=1โˆžf(k)converges.

(d) True or False: The harmonic series converges.

(e) True or False: If p>1, the series โˆ‘k=1โˆžk-pconverges.

(f) True or False: If f(x)โ†’0as xโ†’โˆž, then โˆ‘k=1โˆžf(k) converges.

(g) True or False: If โˆ‘k=1โˆžf(k)converges, then f(x)โ†’0as xโ†’โˆž.

(h) True or False: If โˆ‘k=1โˆžak=Land {Sn}is the sequence of partial sums for the series, then the sequence of remainders {L-Sn}converges to 0.

Given thata0=-3,a1=5,a2=-4,a3=2andโˆ‘akk=2โˆž=7, find the value ofrole="math" localid="1648828803227" โˆ‘akk=3โˆž.

Explain why the integral test may be used to analyze the given series and then use the test to determine whether the series converges or diverges.

โˆ‘k=2โˆžโ€Š1k(lnโกk)2

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