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In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak}and {bk}such that the sequence {ak.bk}diverges.

Short Answer

Expert verified

The examples of such divergent sequence is {ak}={k} and {bk}={k}.

Step by step solution

01

Step 1. Given Information.

Two divergent sequences {ak}and {bk}such that the sequence {ak.bk} is divergent.

02

Step 2. Consider the sequence.

Consider the sequence,

{ak}={k}{bk}={k}

Both are monotonically increasing function and are not bounded above.

So the sequences are divergent.

03

Step 3. Explanation of the statement.

The product of the sequence {ak.bk}={k2}is again a strictly increasing sequence and not bounded above.

So the resultant sequence is also divergent.

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