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In Exercises 31–36 provide the first five terms of the given sequence. Unless specified, assume that the first term has index 1.

ak=cos(kx)xk+k2

Short Answer

Expert verified

The first five terms arecos(x)x+1,cos(2x)x2+4,cos(3x)x3+9,cos(4x)x4+16,cos(5x)x5+25.

Step by step solution

01

Step 1. Given information.

The given series isak=cos(kx)xk+k2.

02

Step 2. First term.

The general sequence is ak=cos(kx)xk+k2.

Put k=1,

a1=cos(1x)x1+12=cos(x)x+1

03

Step 3. Remaining terms.

Now, put,

k=2,a2=cos(2x)x2+22k=3a3=cos(3x)x2+32k=4a4=cos(4x)x4+162k=5a5=cos(5x)x4+52

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