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In Exercises 21–28 provide the first five terms of the series.

n=3(2n+1)

Short Answer

Expert verified

Ans: The five terms of the series are7,9,11,13,15

Step by step solution

01

Step 1. Given information: 

n=3(2n+1)

02

Step 2. Finding the first term of the series:

The first term of the series n=3(2n+1)is obtained by substituting n=3in $2 n+1$. Therefore, the value at n=3is:

2n+1=2(3)+1(Substituting)

=6+1

=7

The first term of the series n=3(2n+1) is 7 .

03

Step 3. Finding the second term of the series:

The second term of the series n=3(2n+1)is obtained by substituting n=4in 2n+1. Therefore, the value at n=4is:

2n+1=2(4)+1(Substituting)

=8+1=9

The second term of the series n=3(2n+1)is 9 .

04

Step 4. Finding the third term of the series:

The third term of the series $n=3(2n+1)$ is obtained by substituting n=5in 2n+1. Therefore, the value at n=5is:

2n+1=2(5)+1(Substituting)

=10+1

=11

The third term of the series n=3(2n+1)is 11 .

05

Step 5. Finding the fourth term of the series:

The fourth term of the series n=3(2n+1)is obtained by substituting n=6in 2n+1. Therefore, the value at n=6is:

2n+1=2(6)+1(Substituting)

=12+1

=13

The fourth term of the series n=3(2n+1)is 13 .

06

Step 6. Finding the fifth term of the series:

The fifth term of the series n=3(2n+1)is obtained by substituting n=7in 2n+1. Therefore, the value at n=7is:

2n+1=2(7)+1(Substituting)

=14+1

=15

The fifth term of the series n=3(2n+1)is 15 .

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