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Find two convergent geometric seriesk=0ak=Land k=0bk=Mwith all positive terms such that k=0akbkbk converges but whose sum is not LM.

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Short Answer

Expert verified

Ans:

part (a). The convergent geometric seriesk=0ak=k=014k

part (b). The convergent geometric seriesk=0bk=k=012k

part (c). The serise is convergek=0akbk=k=012k

part (d). The series k=0akbk=k=012kconverge to the sum 2

The series k=0akbk=k=012kdo not converge to the sum of k=0akk=0bk.

Step by step solution

01

Step 1. Given information: 

Consider the two convergent geometric series k=0ak=Land k=0bk=Msuch that k=0ak·bkconverge.

02

Step 2. Finding the convergent geometric series ∑k=0∞ak=L

Consider the geometric series k=0ak=k=014k.

The series k=014kis a geometric series with common ratior=14, which is less than 1 .

The geometric series with ratio less than 1 is convergent.

Therefore, k=0ak=k=014k is convergent.

03

Step 3. Checking the convergent geometric series :

s=11-14(Sumofgeometricseries)=44-1=43theseriesk=0ak=k=014kisconvergetothesum43

04

Step 4. Finding the convergent geometric series ∑k=0 ∞bk =M

Consider the geometric series k=0bk=k=012k.

The series k=012kis a geometric series with common ratio r=12, which is less than 1 . The geometric series with ratio less than 1 is convergent.

Therefore, k=0bk=k=012k is convergent.

05

Step 6. Checking the convergent geometric series :

s=11-12(Sumofgeometricseries)=22-1=21theseriesk=0bk=k=012kisconvergetothesum2

06

Step 6. Finding series converge to LM :

The series k=0akbk is

k=0akbk=k=02k4k=k=012k

The series k=014kis a geometric series with common ratio r=12, which is less than 1 . The geometric series with ratio less than 1 is convergent.

Therefore, k=0akbk=k=012k is convergent.

07

Step 7. Checking the convergent geometric series :

s=11-12(Sumofgeometricseries)=22-1=21theseriesk=0akbk=k=012kisconvergetothesum2

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