Question

Give examples of sequences satisfying the given conditions or explain why such an example cannot exist.

Two convergent sequences$\left\{a_k\right\},\left\{b_k\right\}$such that the sequence$\left\{\frac{a_k}{b_k}\right\}$diverges.

Short answer

Examples satisfying the given conditions is $$\begin{gathered} \left\{a_k\right\}=\left\{\frac{1}{k}\right\}, \\ \left\{b_k\right\}=\left\{\frac{1}{k^2}\right\} \end{gathered}$$.

Step-by-step solution

Step 1. Given information.

Consider the given question,

Two convergent sequences are$\left\{a_k\right\},\left\{b_k\right\}$.

Step 2. Find if the sequences converges.

Consider the sequence $\left\{a_k\right\}=\left\{\frac{1}{k}\right\}$.

The sequence is strictly decreasing and is bounded.

Therefore, the sequence is convergent and converges to $0$.

Consider the sequence role="math" localid="1649176751776" $\left\{b_k\right\}=\left\{\frac{1}{k^2}\right\}$.

The sequence is strictly decreasing and is bounded.

Therefore, the sequence is convergent and converges to$0$.

Step 3. Find if the sequence satisfies the conditions.

The sequence $\left\{\frac{a_k}{b_k}\right\}=\left\{k\right\}$is increasing sequence and is not bounded above.

The monotonically increasing sequence which is bounded above is convergent.

The sequence $\left\{\frac{a_k}{b_k}\right\}=\left\{k\right\}$is increasing sequence and is not bounded above.

Therefore, the sequence is divergent.

Hence, the two convergent sequences $\left\{a_k\right\},\left\{b_k\right\}$such that $\left\{\frac{a_k}{b_k}\right\}$is divergent are$$\begin{gathered} \left\{a_k\right\}=\left\{\frac{1}{k}\right\}, \\ \left\{b_k\right\}=\left\{\frac{1}{k^2}\right\} \end{gathered}$$