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Graph the equations in Exercises 25–32 in the polar plane. Compare your graphs with the corresponding graphs in Exercises 17–24.

r=secθ

Short Answer

Expert verified

The required graph is as follows,

Step by step solution

01

Step 1. Given Information.

The polar equation isr=secθ.

02

Step 2. Explanation. 

Make a table.

θ
0
π
2π
r=secθ
1-11
03

Step 3. Draw the graph.

The required graph is as follows,

04

Step 4. Compare the graph.

The graph of equation in polar plane is a vertical line parallel to y-axis at distance 1 unit and the graph in θr-planeis as follows.

As we have seen in both the graphs, it is observed that one graph is plotted in polar form and one graph is plotted in algebraic form. Both the graphs are different.

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