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Prove Theorem 9.20 (b). That is, show that the graph of the equation satisfiesy2B2-x2A2=1 Definition 9.19, where the points with coordinates 0,±A2+B2 are the foci of the hyperbola

Short Answer

Expert verified

Hence, proved

Step by step solution

01

Given information

The given equation of a parabola isy2B2-x2A2=1

02

Stp 2: Graph the parabola and find the vertices and foci.

The graph of the parabola y2B2-x2A2=1is ,

The coordinates of the hyperbola are0,±A2+B2

As, from the graph it is clear that the points with coordinates 0,±A2+B2

are the foci of the hyperbola.

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