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Chapter 9: Q. 26 (page 747)

Graph the equations in Exercises 25–32 in the polar plane. Compare your graphs with the corresponding graphs in Exercises 17–24 .
$r = \frac{1}{2} - \sin θ$

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Step by step solution

Step 1. Given information.

The equation of the curve:

$r = \frac{1}{2} - \sin θ$

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Most popular questions from this chapter

Complete example 2 by evaluating the integral expression

$\int_{0}^{\frac{2 π}{3}} {(\frac{1}{2} + \cos θ)}^{2} d θ - \int_{π}^{\frac{4 π}{3}} {(\frac{1}{2} + \cos θ)}^{2} d θ$

In exercise 26-30 Find a definite integral that represents the length of the specified polar curve and then find the exact value of integral

$r = e^{θ} f o r 2 k π \leq θ \leq 2 (k + 1) π$

Sketch the graphs of the equations

$r = \frac{2}{2 + \cos θ}$ and localid="1649860998050" $r = \frac{2}{2 + \sin θ}$

What is the relationship between these graphs? What is the eccentricity of each graph?

In Exercises 24–31 find all polar coordinate representations for the point given in rectangular coordinates.

$(3, - 3)$

in exercise 31-36 find a definite integral that represents the length of the specified polar curve, and then use graphing calculator or computer algebra system to approximate the value of integral

one petal of the polar rose $r = \cos 3 θ$

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Graph the equations in Exercises 25–32 in the polar plane. Compare your graphs with the corresponding graphs in Exercises 17–24 .
$r = \frac{1}{2} - \sin θ$

Short Answer

Step by step solution

Step 1. Given information.

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Graph the equations in Exercises 25–32 in the polar plane. Compare your graphs with the corresponding graphs in Exercises 17–24 .r=12-sinθ

Short Answer

Step by step solution

Step 1. Given information.

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Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Pure Maths

Decision Maths

Calculus

Discrete Mathematics

Geometry

Study anywhere. Anytime. Across all devices.

Graph the equations in Exercises 25–32 in the polar plane. Compare your graphs with the corresponding graphs in Exercises 17–24 .
$r = \frac{1}{2} - \sin θ$