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Evaluate each of the double integral in the exercise 37-54 as iterated integrals

R(3-x+4y)dAwhereR={(x,y)|0x1,-1y3}

Short Answer

Expert verified

The value of integral is 26units.

Step by step solution

01

Given information

We are given an integral as

R(3-x+4y)dAwhereR={(x,y)|0x1,-1y3}

02

Step 2; Use iterated integrals

We get,

-1301(3-x+4y)dxdy=-13[3x-x22+4xy]10dy=-13[52+4y]dy=[52y+2y2]3-1=26

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