Question

The volume increment $dV=---$when you use cylindrical coordinates to evaluate a triple integral. Why is this the standard order of integration for cylindrical coordinates?

Short answer

The volume increment is$rdrdzd\theta$.

Step-by-step solution

Given Information

It is given that we need to evaluate volume increment by using cylindrical coordinates.

Explanation

Mathematically we can write,

$\int \int \int f\left(r,\theta ,z\right)dV=\int \int \int f\left(r,\theta ,z\right)rdzdrd\theta$

Comparing we get,

$dV=rdzdrd\theta$

For simplest order of integration $r$is expressed in terms of $\theta$