Open In App

Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Chapter 13: Q. 14 (page 1003)

Explain why using an iterated integral to evaluate a double integral is often easier than using the definition of the double integral to evaluate the integral.

Short Answer

Expert verified

Ans:

Step by step solution

Step 1. Given information:

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evaluate each of the double integral in the exercise 37-54 as iterated integrals

$\int \int_{R} (2 - 3 x^{2} + y^{3}) d A W h e r e R = {(x, y) | - 3 \leq x \leq 2, 3 \leq y \leq 5}$

Evaluate the triple integrals over the specified rectangular solid region.

$\begin{aligned} ∭_{R} (x + 2 y + 3 z) d V, where \\ R = {(x, y, z) ∣ 0 \leq x \leq 4, 1 \leq y \leq 5, and 2 \leq z \leq 7} \end{aligned}$

Describe the three-dimensional region expressed in each iterated integral in Exercises 35–44.

$\int_{0}^{3} \int_{0}^{3} \int_{0}^{3 - y} f (x, y, z) d z d y d x$

$How many summands are in \sum_{j = j_{0}}^{m} \sum_{k = k_{0}}^{n} j^{k} ?$

Evaluate each of the integrals in exercise 33-36 as iterated integrals and then compare your answers with those you found in exercise 29-32

$\int \int_{R} x^{2} y^{3} d A W h e r e R = {(x, y) | 1 \leq x \leq 3, 0 \leq y \leq 2}$

See all solutions

Recommended explanations on Math Textbooks

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free

Explain why using an iterated integral to evaluate a double integral is often easier than using the definition of the double integral to evaluate the integral.

Short Answer

Step by step solution

Step 1. Given information:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Probability and Statistics

Mechanics Maths

Logic and Functions

Pure Maths

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Company

Product

Help