Question

Translate expressions written in Leibniz notation to “prime” notation, and vice versa.

${\overline{)\frac{dg}{dt}}}_{t=3}$

Short answer

${\overline{)\frac{dg}{dt}}}_{t=3}=g^{\text{'}}\left(3\right)$

Step-by-step solution

Given Information

The expression is${\overline{)\frac{dg}{dt}}}_{t=3}$

Simplification

${\overline{)\frac{dg}{dt}}}_{t=3}$is written in Leibnitz notation.

It mean differentiation of function role="math" localid="1650913719801" $g$w.r.t $t$at $t=3$.

In prime notation, it is written as$g^{\text{'}}\left(t\right)$