Question

Fill in the blank:$(f+g)\text{'}\left(x\right)=\_\_\_\_\_\_\_\_\_\_.$

Short answer

$(f+g)\text{'}\left(x\right)=f\text{'}\left(x\right)+g\text{'}\left(x\right).$

Step-by-step solution

Given Information  

The given expression is$(f+g)\text{'}\left(x\right).$

Simplification 

$(f+g)\text{'}\left(x\right)=f\text{'}\left(x\right)+g\text{'}\left(x\right).$

The derivative of$(f+g)\left(x\right)$is$f\text{'}\left(x\right)+g\text{'}\left(x\right).$