Question

Fill in the blank:$\left(kf\right)\text{'}\left(x\right)=\_\_\_\_\_\_\_\_.$

Short answer

$\left(kf\right)\text{'}\left(x\right)=k.f\text{'}\left(x\right).$

Step-by-step solution

Given Information 

The given expression is$\left(kf\right)\text{'}\left(x\right).$

Simplification 

$$\begin{gathered} \left(kf\right)\text{'}\left(x\right)=k.f\text{'}\left(x\right). \\ Thederivativeof\left(kf\right)\text{'}\left(x\right)isk.f\text{'}(*x). \end{gathered}$$