Question

Fill in the blank:

$\frac{d}{dx}\left(se{c}^{-1}x\right)=---$

Short answer

$\frac{d}{dx}\left(se{c}^{-1}x\right)=\frac{1}{\left|x\right|\sqrt{x^2-1}}$

Step-by-step solution

Given Information

The given expression is$\frac{d}{dx}\left(se{c}^{-1}x\right)$

Simplification

Differentiation of $se{c}^{-1}x$is $\frac{1}{\left|x\right|\sqrt{x^2-1}}$

$\Rightarrow \frac{d}{dx}\left(se{c}^{-1}x\right)=\frac{1}{\left|x\right|\sqrt{x^2-1}}$