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Use integration formulas to solve each integral in Exercises 21–62. You may have to use algebra, educated guess-and-check, and/or recognize an integrand as the result of a product, quotient, or chain rule calculation. Check each of your answers by differentiating.

(sin2x+cos2x)dx

Short Answer

Expert verified

The solution of the integral is x+C.

Step by step solution

01

Step 1. Given Information. 

The given integral is(sin2x+cos2x)dx.

02

Step 2. Solve. 

By solving the integral we get,

(sin2x+cos2x)dx=1dxsin2x+cos2x=1=x+C

03

Step 3. Verification. 

To verify the answer we differentiate x+Cit.

On differentiating we get,

x+C=ddxx+ddxC=1+0=1=sin2x+cos2xsin2x+cos2x=1

Hence proved.

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Most popular questions from this chapter

Approximate the same area as earlier but this time with eight rectangles is this over approximation or under approximation of the exact area under the graph

Use the Fundamental Theorem of Calculus to find the exact values of the given definite integrals. Use a graph to check your answer.

112x4xdx

For each function f and interval [a, b] in Exercises 27–33, use the given approximation method to approximate the signed area between the graph of f and the x-axis on [a, b]. Determine whether each of your approximations is likely to be an over-approximation or an under-approximation of the actual area.

f(x)=sin(x),[a,b]=[0,π], n = 3 with

a) Trapezoid sim b) Upper sum

Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The absolute area between the graph of f and the x-axis on [a, b] is equal to|abf(x)dx|.

(b) True or False: The area of the region between f(x) = x − 4 and g(x) = -x2on the interval [−3, 3] is negative.

(c) True or False: The signed area between the graph of f on [a, b] is always less than or equal to the absolute area on the same interval.

(d) True or False: The area between any two graphs f and g on an interval [a, b] is given by ab(f(x)-g(x))dx.

(e) True or False: The average value of the function f(x) = x2-3 on [2, 6] is

f(6)+f(2)2= 33+12= 17.

(f) True or False: The average value of the function f(x) = x2-3on [2, 6] is f(6)-f(2)4= 33-14= 8.

(g) True or False: The average value of f on [1, 5] is equal to the average of the average value of f on [1, 2] and the average value of f on [2, 5].

(h) True or False: The average value of f on [1, 5] is equal to the average of the average value of f on [1, 3] and the average value of f on [3, 5].

If -23f(x)dx=4,-26f(x)dx=9,-23g(x)dx=2and 36g(x)dx=3,then find the values of each definite integral in Exercises 29-40. If there is not enough information, explain why.

36fxdx.

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