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For each function f that follows, construct sign charts forf, f',and f '', if possible. Examine function values or limits at any interesting values and at ±∞. Then interpret this information to sketch a labeled graph of f.

f(x)=x3-2x2-4x+8

Short Answer

Expert verified

sign charts forf, f',and f ''are following.

Graph of function is following.

Step by step solution

01

Step 1. Given information. 

The given function isf(x)=x3-2x2-4x+8.

02

Step 2. Roots of the function.

Equate the function to zero.

f(x)=0x3-2x2-4x+8=0x2(x-2)-4(x-2)=0(x2-4)(x-2)=0x=2,-2.

Roots of the function.

03

Step 3. critical points of the function.

Determine the first derivative of the function.

f'(x)=ddxx3-2x2-4x+8f'(x)=3x2-4x-4

critical points of the function.

role="math" localid="1648666452201" f'(x)=03x2-4x-4=03x2-6x+2x-4=03x(x-2)+2(x-2)=0(3x+2)(x-2)=0x=2,-23

f' is positive on interval -,-23&2,and negative on the interval-23,2.

So f is increasing on intervals -,-23&2,and decreasing on the interval-23,2.

04

Step 4. concavity of the function.

find the second derivative of the function.

f''(x)=ddx3x2-4x-4f''(x)=6x-4

Roots of the second derivative of the function.

f''(x)=06x-4=0x=23

f'' is positive on the interval 23,and negative on the interval-,23.

So f is concave up on interval 23,and concave down on the interval -,23.

So the sign chart is the following.

05

Step 5. Graph of function.

The graph of the function is the following.

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