Question

The hydrostatic force exerted by water on one of the sides of a small cubical tank that is 4 feet to a side.

Short answer

$7000lb$

Step-by-step solution

Step1. Given Information

Side of a cubical tank= 4feet

Step2. Calculate

$$\begin{gathered} F=Force \\ P=Pressure \\ A=Area \\ \rho =Density \\ F=PA=\rho gdA=\delta dA \\ Accordingtoquestion, \\ \delta =62.5x \\ A=2x \\ dA=2dx \\ Therefore, \\ dF=\delta dA \\ =62.5x*2dx \\ F={\int }_3^{11}2*62.5*xdx \\ F=2*62.5{{\left[\frac{x^2}{2}\right]}_3}^{11}F=2*62.5[\frac{{11}^2}{2}-\frac{3^2}{2}] \\ =7000lb. \end{gathered}$$