Question

Use antidifferentiation and/or separation of variables to solve the given differential equations. Your answers will involve unsolved constants.

$\frac{dy}{dx}={\left(x^3+4\right)}^2$

Short answer

Ans: The solution of the differential equation $\frac{dy}{dx}={\left(x^3+4\right)}^2$is $\frac{1}{7}{x}^7+2x^4+16x+C$.

Step-by-step solution

Step 1. Given information.

given,

$\frac{dy}{dx}={\left(x^3+4\right)}^2$

Step 2. Consider the differential equation defined by equation (1) given below and solve it by using antidifferentiation and/or separation of the variable method.

$\frac{dy}{dx}={\left(x^3+4\right)}^2.....\left(1\right)$

Step 3. Now,

Note that the differential equation $\left(1\right)$does not contain the dependent variable at all, so technically the variables have already been separated. So, the differential equation can be solved by antidifferentiation. Thus, the solution of the differential equation is obtained by integrating both the sides

$\begin{array}{r}\int dy=\int {\left(x^3+4\right)}^{2}dx\\ =\int \left(x^6+8x^3+16\right)dx\\ =\int x^{6}dx+8\int x^{3}dx+16\int dx\\ =\frac{1}{7}{x}^7+2x^4+16x+C\end{array}$

Hence, a solution to the differential equation role="math" localid="1649151183048" $\frac{dy}{dx}={\left(x^3+4\right)}^2$is$\frac{1}{7}{x}^7+2x^4+16x+C\text{.}$