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WriteeachofthelimitsinExercises911intermsofdefiniteintegrals,andidentifyasolidofrevolutionwhosevolumeisrepresentedbythatdefiniteintegral:limnk=1nπ(1+yk*)23n,withyk*=yk=1+k3n

Short Answer

Expert verified

Thesolidofrevolutionisformedbyrotatingtheregionbelowthestraightline(1+y)aroundthey-axisintheinterval[2,5].

Step by step solution

01

Step 1. Given Information is:

limnk=1nπ(1+yk*)23n,withyk*=yk=1+k3n

02

Step 2. Finding Interval

Theexpressionforinputvariableisgivenas:yk=a+k(y)yk=a+kb-anComparethisexpressionwiththegivenexpressiontohavethevaluesasa=2andb-a=3.Usetheseequations,toderiveb=5.Thus,theintervalofintergrationis[2,5].

03

Step 3. Creating definite integral

Tocreatethedefiniteintegral,replacethesummationsignbythesignofdefiniteintegral,ybydy:limnk=1nπ(1+yk*)23n=25π(1+y)2dxlimnk=1nπ(1+yk*)23n=π25(1+y)2dx

04

Step 4. Result

Thisintegralcanbecomparedwiththeexpressionforsolidofrevolutionaroundy-axisgivenasV=πabfy2dxComparethisexpressionwiththedefiniteintegralderivedabovetodeterminethefunctionforsolidofrevolution.Itisf(y)=(1+y)intheinterval[2,5].Thisrepresentsastraightline.Thus,thesolidofrevolutionisformedbyrotatingtheregionbelowthisstraightlinearoundthey-axisintheabovementionedinterval.

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