Question

The work involved in lifting an object is the product of the weight of the object and the distance it must be lifted. Suppose a flat, wide cylinder that weighs 50 pounds must be lifted from ground level to a height of 10 feet. How much work does this require, in footpounds?

Short answer

The work involved in lifting of the cylinder is$500$foot pounds.

Step-by-step solution

Step 1. Given information

The work involved in lifting of object is the product of the weight of object and distance it must be lifted.

The wight of cylinder is 50 pounds

The distance of lifting cylinder is 10 feet.

Step 2. To find work involved

The work involved in lifting of cylinder is:

$$\begin{gathered} w=50\times 10 \\ =500 \end{gathered}$$

So $500$foot pound work is involved in lifting of the cylinder.