Chapter 4: Problem 24
Use the method of direct proof to prove the following statements. If \(n \in \mathbb{N}\) and \(n \geq 2,\) then the numbers \(n !+2, n !+3, n !+4, n !+5, \ldots, n !+n\) are all composite. (Thus for any \(n \geq 2,\) one can find \(n-1\) consecutive composite numbers. This means there are arbitrarily large "gaps" between prime numbers.)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.