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Consider the functions \(f, g: \mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z} \times \mathbb{Z}\) defined as \(f(m, n)=\left(m n, m^{2}\right)\) and \(g(m, n)=(m+1, m+n)\). Find the formulas for \(g \circ f\) and \(f \circ g\).

Short Answer

Expert verified
The functions \(g \circ f\) and \(f \circ g\) are given by \(g \circ f(m, n) = (mn + 1, mn + m^2)\) and \(f \circ g(m, n) = (m^2 + 2mn + n, m^2 + 2m + 1)\) respectively.

Step by step solution

01

Define the Functions

The two functions are defined as follows: \(f(m, n) = (mn, m^2)\) and \(g(m, n) = (m+1, m+n)\). These are functions in \(\mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z} \times \mathbb{Z}\).
02

Find \(g \circ f\)

When finding \(g \circ f\), we apply 'f' first, and then 'g'. The function 'f' produces (mn, m^2). This output becomes the input for 'g'. Thus: \(g(f(m, n)) = g(mn, m^2) = ((mn)+1, (mn) + (m^2)) = (mn + 1, mn + m^2)\).
03

Find \(f \circ g\)

When finding \(f \circ g\), we apply 'g' first, and then 'f'. The function 'g' produces (m+1, m+n). This output becomes the input for 'f'. Thus: \(f(g(m, n)) = f(m+1, m+n) = ((m+1)(m+n), (m+1)^2) = (m^2 + 2mn + n, m^2 + 2m + 1)\).

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