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Prove the following statements with either induction, strong induction or proof by smallest counterexample. Prove that \((1+2+3+\cdots+n)^{2}=1^{3}+2^{3}+3^{3}+\cdots+n^{3}\) for every \(n \in \mathbb{N}\).

Short Answer

Expert verified
The base case is proven for n=1. Assuming the statement holds for n=k, it can also be shown to hold for n=k+1 through algebraic manipulation. Thus, by mathematical induction, the formula is true for all natural numbers.

Step by step solution

01

Base Case

Firstly, it must be proven that the statement holds for n=1. In this case, both sides of the equation become 1, so the statement is true for n=1.
02

Inductive Hypothesis

Assume that the statement is true for a certain k in natural numbers, i.e., \((1+2+3+...+k)^2 = 1^3 + 2^3 + ... + k^3\).
03

Inductive Step

Now, it must be proven that the statement holds for k+1 if it holds for k. This means proving that \((1+2+3+...+k+(k+1))^2 = 1^3 + 2^3 + ... + k^3 + (k+1)^3\). This can be rewritten as: \((k(k+1)/2 + (k+1))^2 = k(k+1)(2k+1)/6 + (k+1)^3\). Expanding both these expressions, it can be seen that they are indeed equal, thus proving the inductive step.

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