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Write out the indicated sets by listing their elements between braces. $$ \left\\{x \in \mathbb{R}: x^{2}=x\right\\} \times\left\\{x \in \mathbb{N}: x^{2}=x\right\\} $$

Short Answer

Expert verified
The product set is \((0, 1), (1, 1)\).

Step by step solution

01

Solve the Equation for the Real Number Set

The equation for the real number set is \(x^2 = x\). Now subtract \(x\) from both sides of the equation to get \(x^2 - x = 0\). This equation can be factored as \(x(x - 1) = 0\). Setting each factor equal to zero and solving for \(x\) gives \(x = 0\) or \(x = 1\). So, the real number set is \(\{0, 1\}.
02

Solve the Equation for the Natural Number Set

The equation for the natural number set is \(x^2 = x\). This is the exact same equation we solved above in Step 1. However, the domains of the equations are different. We need to find the natural numbers \(x\) that satisfy \(x^2 = x\), which are also \(x = 0\) or \(x = 1\). As \(0\) isn't a natural number, the natural number set is \(\{1\}.
03

Write the Product Set

The exercise asks for the product set, which is made up of ordered pairs from the real number set and the natural number set. Each ordered pair consists of one element from each set. The product set is \((0, 1), (1, 1)\).

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