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Suppose that \(|A|=m\) and \(|B|=n .\) Find the following cardinalities. $$ |\\{X \in \mathscr{P}(A):|X| \leq 1\\}| $$

Short Answer

Expert verified
The cardinality of the mentioned subsets of the power set is 'm+1'.

Step by step solution

01

Understanding Cardinality and Power set

Recall that cardinality of a set refers to the number of elements in a set. If the cardinality of Set A is m it means there are 'm' elements in set A; similarly, if the cardinality of Set B is n, it means that there are 'n' elements in set B. The Power set refers to all possible subsets of a particular set, including the set itself and the empty set. For any set with 'm' elements, the power set will contain \(2^m\) subsets.
02

Identifying the required subsets

The problem asks for the cardinality of subsets of the power set of A such that each subset contains no more than one element. This interpret as subsets that are either an empty set, or a subset containing just a single element from set A.
03

Calculate the cardinality

Since the subsets of the power set of A can either be empty or contain one element, there are 'm+1' such subsets. The '+1' is to account for the empty set.

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