Chapter 9: Problem 13
Evaluate the expression given that \(\cos a=\frac{4}{5}\) with \(0
Short Answer
Expert verified
\(\cos (a-b)= -\frac{77}{85}\)
Step by step solution
01
Determine the values of sin a and cos b
Given that \(\cos a = \frac{4}{5}\) and \(\sin b = -\frac{15}{17}\), calculate \(\sin a\) and \(\cos b\) using the relationship: \(\sin^2 \theta + \cos^2 \theta = 1\), which implies \(\sin \theta = \sqrt{1 - \cos^2 \theta}\) and \(\cos \theta = \sqrt{1 - \sin^2 \theta}\). Now based on the given angles range, take the appropriate sign for the roots, yielding \(\sin a = \frac{3}{5}\) and \(\cos b = -\frac{8}{17}\).
02
Evaluate the expression
Substitute the values of \(\cos a\), \(\cos b\), \(\sin a\) and \(\sin b\) into the formula \(\cos (a-b) = \cos a \cos b + \sin a \sin b\). This leads to \(\cos (a-b) = \frac{4}{5} \times -\frac{8}{17} + \frac{3}{5} \times -\frac{15}{17} = -\frac{32}{85} - \frac{45}{85} = -\frac{77}{85}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine of Angle Difference
Evaluating the cosine of an angle difference involves one of the key formulas in trigonometry: \( \cos (\alpha - \beta) = \cos \alpha \cos \beta + \sin \alpha \sin \beta \). This formula is derived from the trigonometric sum and difference identities and is essential for solving problems where two angles are involved, such as \(\cos (a-b)\) in the given exercise.
To use this identity effectively, one must remember to retain the signs of each trigonometric function based on the quadrants in which the angles \(\alpha\) and \(\beta\) lie. As we know from the ranges given for \(a\) and \(b\) in the original problem, \(a\) is in the first quadrant where both sine and cosine are positive, while \(b\) is in the fourth quadrant where sine is negative, and cosine is positive. This understanding helps in ascertaining the correct signs when substituting the values into the identity.
To use this identity effectively, one must remember to retain the signs of each trigonometric function based on the quadrants in which the angles \(\alpha\) and \(\beta\) lie. As we know from the ranges given for \(a\) and \(b\) in the original problem, \(a\) is in the first quadrant where both sine and cosine are positive, while \(b\) is in the fourth quadrant where sine is negative, and cosine is positive. This understanding helps in ascertaining the correct signs when substituting the values into the identity.
Pythagorean Trigonometric Identity
The Pythagorean trigonometric identity is a fundamental concept in trigonometry and states that for any angle \(\theta\), the sum of the squares of the sine and cosine of \(\theta\) equals one: \( \sin^2 \theta + \cos^2 \theta = 1 \). This identity is derived from the Pythagorean theorem, which relates to the sides of a right angle triangle.
In our exercise, the Pythagorean identity helps to determine the missing sine or cosine values when one is known. For example, knowing \(\cos a = \frac{4}{5}\), you can find \(\sin a\) by rearranging the identity as \(\sin a = \sqrt{1 - \cos^2 a}\), selecting the positive square root because angle \(a\) lies in the first quadrant where sine is positive.
In our exercise, the Pythagorean identity helps to determine the missing sine or cosine values when one is known. For example, knowing \(\cos a = \frac{4}{5}\), you can find \(\sin a\) by rearranging the identity as \(\sin a = \sqrt{1 - \cos^2 a}\), selecting the positive square root because angle \(a\) lies in the first quadrant where sine is positive.
Trigonometric Function Values
The trigonometric function values for sine and cosine are based on the position of angles on the unit circle. These values can be either positive or negative, depending on the quadrant in which the angle lies.