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Write the first six terms of the sequence. (See Example 1.) \(a_n=-n^2\)

Short Answer

Expert verified
The first six terms of the sequence are: -1, -4, -9, -16, -25, -36

Step by step solution

01

Determine the first term

The first term in the sequence is gotten when \(n = 1\), substituting this into the function \(a_n = -n^2\), we get \(a_1 = -(1)^2 = -1\).
02

Determine the second term

The second term in the sequence is gotten when \(n = 2\), substituting this into the function \(a_n = -n^2\), we get \(a_2 = -(2)^2 = -4\).
03

Determine the third term

The third term in the sequence is gotten when \(n = 3\), substituting this into the function \(a_n = -n^2\), we get \(a_3 = -(3)^2 = -9\).
04

Determine the fourth term

The fourth term in the sequence is gotten when \(n = 4\), substituting this into the function \(a_n = -n^2\), we get \(a_4 = -(4)^2 = -16\).
05

Determine the fifth term

The fifth term in the sequence is gotten when \(n = 5\), substituting this into the function \(a_n = -n^2\), we get \(a_5 = -(5)^2 = -25\).
06

Determine the sixth term

The sixth term in the sequence is gotten when \(n = 6\), substituting this into the function \(a_n = -n^2\), we get \(a_6 = -(6)^2 = -36\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Negative Quadratic Functions
A negative quadratic function takes the form of an equation like \( a_n = -n^2 \). It is a type of quadratic function because it includes \( n^2 \), meaning the variable is squared. When a quadratic function has a negative leading coefficient (in this case, the coefficient is \(-1\)), the graph of the function is a downward-opening parabola. This means that instead of curving upwards, like a happy face, it curves downward, like a sad face.
This implies that as the values for \( n \) (in our sequence) increase, the output values \( a_n \) will decrease. Quadratic functions are significant because they appear very often in real-world situations, from physics problems to financial equations, illustrating how rapidly changing processes behave.
In the context of the sequence \( a_n = -n^2 \), each output is dependent on the square of the input \( n \) but made negative, showing rapid descent in values as \( n \) increases.
Key Features of Sequence Terms
In mathematical sequences, each number is called a term, and they are usually written in order. Sequences can follow various rules or formulas to determine these terms. When you know the rule, you can find any term in the sequence by substituting the appropriate value of \( n \) into your formula.
For example, the sequence described by \( a_n = -n^2 \) produces the terms \( -1, -4, -9, -16, -25, -36 \) as \( n \) goes from 1 to 6. Each of these numbers is a part of the sequence, and they follow a clear pattern dictated by the squaring of \( n \), followed by reversing the sign (due to the negative in the formula).
This method is straightforward and helps predict terms in a sequence without calculating each time. Sequence terms are essential in creating patterns that can be identified and analyzed, providing insight into more significant mathematical and real-world phenomena.
Algebraic Expression Evaluation Skills
Evaluating algebraic expressions is a fundamental skill necessary for solving mathematical problems. This involves substituting numbers for variables and performing the arithmetic operations to find a result. For the sequence \( a_n = -n^2 \), you substitute each value of \( n \) into the expression to find the corresponding term.
For instance, substituting \( n = 1 \) results in \( a_1 = -(1)^2 = -1 \). Similarly, when \( n = 2 \), you calculate \( a_2 = -(2)^2 = -4 \), and this continues for subsequent terms. By systematically evaluating these expressions, you can determine each term of the sequence efficiently.
Mastering this technique is crucial because it helps break down more complex problems into manageable steps, and it's widely applicable across various fields of study in mathematics, including calculus, trigonometry, and beyond. Ensuring accuracy at each step of evaluation is pivotal to solving more comprehensive mathematical challenges.

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Most popular questions from this chapter

Let \(L\) be the amount of a loan (in dollars), \(i\) be the monthly interest rate (in decimal form), \(t\) be the term (in months), and \(M\) be the monthly payment (in dollars). a. When making monthly payments, you are paying the loan amount plus the interest the loan gathers each month. For a 1-month loan, \(t=1\), the equation for repayment is \(L(1+i)-M=0\). For a 2-month loan, \(t=2\), the equation is \([L(1+i)-M](1+i)-M=0\). Solve both of these repayment equations for \(L\). b. Use the pattern in the equations you solved in part (a) to write a repayment equation for a \(t\)-month loan. (Hint: \(L\) is equal to \(M\) times a geometric series.) Then solve the equation for \(M\). c. Use the rule for the sum of a finite geometric series to show that the formula in part (b) is equivalent to $$ M=L\left(\frac{i}{1-(1+i)^{-t}}\right) . $$ Use this formula to check your answers in Exercises 57 and 58.

Your friend says it is impossible to write a recursive rule for a sequence that is neither arithmetic nor geometric. Is your friend correct? Justify your answer.

In Exercises 15-22, write a rule for the \(n\)th term of the sequence. Then find \(a_7\). \(6,24,96,384, \ldots\)

In Exercises 23-30, write a rule for the \(n\)th term. Then graph the first six terms of the sequence. $$ a_2=30, r=\frac{1}{2} $$

You make a \(500 down payment on a \)3500 diamond ring. You borrow the remaining balance at 10% annual interest compounded monthly. The monthly payment is $213.59. How long does it take to pay back the loan? What is the amount of the last payment? Justify your answer

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