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\(x^2=100-y^2\)

Short Answer

Expert verified
The solution to the equation \(x^2 = 100 - y^2\) is given by \(x = \sqrt{100 - y^2}\) and \(x = -\sqrt{100 - y^2}\).

Step by step solution

01

Identify the Form of the Equation

Recognize that the given equation \(x^2=100-y^2\) is in the form of \(a^2 - b^2\). This pattern can be factored into the form \((a + b)(a - b)\). In this case, \(a\) corresponds to \(x\) while \(b\) is the square root of 100 or 10.
02

Simplify the Equation

The next step is to simplify the equation by moving \(y^2\) to the left side of the equation, so it now reads \(x^2 + y^2 = 100\). This is done using the arithmetic operation of addition.
03

Solving for x

The final step involves isolating \(x\) on one side of the equation. Subtract \(y^2\) from both sides of the equation to get \(x^2 = 100 - y^2\). Then take the square root of both sides, to get \(x = \sqrt{100 - y^2}\). Remember, that there would be two solutions, \(x = \sqrt{100 - y^2}\) and \(x = -\sqrt{100 - y^2}\), due to the property of square roots.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
A quadratic equation is an equation that can be expressed in the standard form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and \(a eq 0\). These equations are fundamental in algebra and appear in many mathematical problems. The key characteristic of a quadratic is the squared term, \(x^2\).

Unlike linear equations, which graph as straight lines, quadratic equations graph as parabolas. Understanding their structure helps in solving them in different ways, such as factoring, completing the square, or using the quadratic formula. In the equation presented, \(x^2 = 100 - y^2\), the term \(x^2\) underlines its quadratic nature.

A key skill is recognizing how to manipulate quadratic equations to find solutions, like rearranging or factoring, allowing for easier problem-solving and solution finding.
Factoring
Factoring is a valuable method used to break down expressions into products of simpler factors. This technique is particularly useful for solving quadratic equations. Factorable quadratics typically show a pattern or structure which helps to simplify the problem-solving process.

One popular pattern is the difference of squares, which follows the identity \(a^2 - b^2 = (a + b)(a - b)\). This method is useful to simplify expressions quickly. In the original exercise, the equation \(x^2 = 100 - y^2\) can be visualized as a difference of two squares by identifying the squared terms \(x^2\) and \(y^2\) against a constant squared term 100 (as \(10^2\)).

By recognizing and applying the difference of squares, you can efficiently rearrange the equation into a factorable format. This reduces complexity and assists in finding the variable values easily.
Pythagorean Theorem
The Pythagorean Theorem is a cornerstone in geometry, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides: \(a^2 + b^2 = c^2\). This theorem connects algebra and geometry, providing insight into the relationship between the lengths of sides in right triangles.

In the exercise, when the equation \(x^2 = 100 - y^2\) is rearranged to \(x^2 + y^2 = 100\), it takes on a form resembling the Pythagorean Theorem. Here, \(x\) and \(y\) can be viewed as the legs of a right triangle whose hypotenuse has a length of 10, as shown by the constant 100 being \(10^2\).

This illustrates the beauty of mathematics where algebraic manipulation meets geometric interpretation, offering a comprehensive approach to solving problems in diverse scenarios.

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Most popular questions from this chapter

The domain of the function \(y=a \sqrt{x}\) is \(x \geq 0\)

\(f(x)=\sqrt{x-3}+3\)

When calibrating a spring scale, you need to know how far the spring stretches for various weights. Hooke's Law states that the length a spring stretches is proportional to the weight attached to it. A model for one scale is \(\ell=0.5 w+3\), where \(\ell\) is the total length (in inches) of the stretched spring and \(w\) is the weight (in pounds) of the object. a. Find the inverse function. Describe what it represents. b. You place a melon on the scale, and the spring stretches to a total length of \(5.5\) inches. Determine the weight of the melon. c. Verify that the function \(\ell=0.5 w+3\) and the inverse model in part (a) are inverse functions.

MULTIPLE REPRESENTATIONS The terminal velocity \(v_t\) (in feet per second) of a skydiver who weighs 140 pounds is given by $$ v_t=33.7 \sqrt{\frac{140}{A}} $$ where \(A\) is the cross-sectional surface area (in square feet) of the skydiver. The table shows the terminal velocities (in feet per second) for various surface areas (in square feet) of a skydiver who weighs 165 pounds. \begin{tabular}{|c|c|} \hline Cross-sectional surface area, \(\boldsymbol{A}\) & Terminal velocity, \(\boldsymbol{v}_{\boldsymbol{t}}\) \\ \hline 1 & \(432.9\) \\ 3 & \(249.9\) \\ 5 & \(193.6\) \\ 7 & \(163.6\) \\ \hline \end{tabular} a. Which skydiver has a greater terminal velocity for each value of \(A\) ? b. Describe how the different values of \(A\) given in the table relate to the possible positions of the falling skydiver.

The domain and range of the function \(y=\sqrt[3]{x-h}+k\) are all real numbers.

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