Chapter 5: Problem 32
In Exercises 27–34, solve the equation. Check your solution(s). $$ (5-x)^{1 / 2}-2 x=0 $$
Short Answer
Expert verified
The valid solution for the equation \((5-x)^{1 / 2}-2 x=0\) is \(x=1\)
Step by step solution
01
Isolate the square root
First arrange the equation and bring constant terms on one side, isolate the square root term on the other, so that the equation becomes \((5-x)^{1 / 2}=2x\)
02
Square both sides
Next square both sides of the equation to remove the square root: \( ((5-x)^{1 / 2})^2=(2x)^2 \), which simplifies to \(5-x=4x^2\)
03
Rearrange into standard quadratic form
Now rearrange the resulting equation into the standard form of a quadratic equation \(ax^2+bx+c=0\). This leads us to the equation \(4x^2+x-5=0\)
04
Solve the quadratic equation
Now, use the quadratic formula to solve the equation. The solutions are \(x1= 1\) and \(x2=-1.25\)
05
Check the solutions
Substitute the values of \(x1\) and \(x2\) into the original equation to verify if they are true solutions. The value \(x=1\) satisfies the original equation while the value \(x=-1.25\) doesn't. So the valid solution is \(x=1\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isolating the Square Root
Isolating the square root is the first crucial step in solving equations that include a square root function. The goal is to rearrange the equation so that the square root is by itself on one side of the equation.
To achieve this, start by moving other terms to the opposite side of the equation. This isolation helps make it easier to eliminate the square root in subsequent steps.
For example, in the equation \((5-x)^{1 / 2} = 2x\), we have isolated the square root term \((5-x)^{1 / 2}\) by moving other terms to the opposite side.
This manipulation sets the stage for the next step: squaring both sides to clear the square root.
To achieve this, start by moving other terms to the opposite side of the equation. This isolation helps make it easier to eliminate the square root in subsequent steps.
For example, in the equation \((5-x)^{1 / 2} = 2x\), we have isolated the square root term \((5-x)^{1 / 2}\) by moving other terms to the opposite side.
This manipulation sets the stage for the next step: squaring both sides to clear the square root.
Quadratic Formula
The quadratic formula is a reliable tool for solving quadratic equations and is especially handy when factoring is difficult or impossible. It is derived from the standard form of a quadratic equation:
By identifying \(a = 4\), \(b = 1\), and \(c = -5\), we plug these values into the quadratic formula, resulting in two potential solutions: \(x = 1\) and \(x = -1.25\).
This method provides a systematic way to solve any quadratic equation, ensuring that no potential solution is overlooked.
- \( ax^2 + bx + c = 0 \)
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
By identifying \(a = 4\), \(b = 1\), and \(c = -5\), we plug these values into the quadratic formula, resulting in two potential solutions: \(x = 1\) and \(x = -1.25\).
This method provides a systematic way to solve any quadratic equation, ensuring that no potential solution is overlooked.
Checking Solutions
Checking solutions is an essential step in the process of solving equations, especially when dealing with square roots and quadratic equations. Once you have found the potential solutions using methods like the quadratic formula, you need to verify them by substituting back into the original equation.
For the potential solutions \(x = 1\) and \(x = -1.25\) found from the quadratic formula step, substituting these back into the original equation \((5-x)^{1 / 2} - 2x = 0\) helps us determine their validity.
For the potential solutions \(x = 1\) and \(x = -1.25\) found from the quadratic formula step, substituting these back into the original equation \((5-x)^{1 / 2} - 2x = 0\) helps us determine their validity.
- When \(x = 1\), the original equation holds true.
- However, when \(x = -1.25\), substituting it shows that the equation becomes invalid.
Standard Form of Quadratic Equation
The standard form of a quadratic equation is an essential format used to simplify, analyze, and solve quadratic expressions. It is represented as:
For instance, after removing the square root by squaring both sides in our given problem, the equation \(5 - x = 4x^2\) is reorganized into the standard form \(4x^2 + x - 5 = 0\).
Each term in the equation has a specific role:
- \( ax^2 + bx + c = 0 \)
For instance, after removing the square root by squaring both sides in our given problem, the equation \(5 - x = 4x^2\) is reorganized into the standard form \(4x^2 + x - 5 = 0\).
Each term in the equation has a specific role:
- \(ax^2\) is the quadratic term, defining the nature of the parabola.
- \(bx\) is the linear term, affecting the slope and direction.
- \(c\) is the constant term, shifting the curve up or down.