Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

\(\frac{\sqrt[3]{5}}{\sqrt[3]{4}}\)

Short Answer

Expert verified
The simplified version of the given expression \(\frac{\sqrt[3]{5}}{\sqrt[3]{4}}\) is \(\sqrt[3]{1.25}\).

Step by step solution

01

Identify the given expression

The given expression is \(\frac{\sqrt[3]{5}}{\sqrt[3]{4}}\). The idea here is to simplify this expression. Since both terms are under the cubic root and in the format of \(\sqrt[3]{a}/\sqrt[3]{b}\), we could apply the quotient rule of radicals here. The quotient rule of radicals states that \(\sqrt[n]{\frac{a}{b}} = \frac{\sqrt[n]{a}}{\sqrt[n]{b}}\), where a and b are positive real numbers and n is an integer.
02

Recall and apply the quotient rule of radicals

The quotient rule of radicals can be applied to our expression. This leads us to \(\sqrt[3]{\frac{5}{4}}\). Now, the expression is in a simpler format.
03

Convert the fraction under the cube root into decimal

The fraction 5/4 can be converted into decimal as \(\sqrt[3]{1.25}\). Now the expression should be simpler to read and understand.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cube Roots
Cube roots are a specific type of radical expression that involves finding a number which, when multiplied by itself three times, gives the original number. For example, the cube root of 8 is 2, because 2 × 2 × 2 = 8. In mathematical notation, cube roots are represented as \(\sqrt[3]{x}\), where \(x\) is the number we want to find the cube root of and 3 is the index indicating it's a cube root.
Cube roots are important in many areas of math and science because they allow us to simplify expressions and solve equations involving cubic terms. Understanding how to work with cube roots will enable you to simplify complex equations and expressions in a more straightforward manner.
Simplifying Expressions
Simplifying expressions involves reducing them to their simplest form. This often means removing unnecessary terms, combining like terms, or using mathematical rules to condense the expression. The goal is to make the expression as easy to work with as possible.
In the context of cube roots and other radicals, simplification can involve applying rules such as the quotient rule of radicals. This rule allows us to combine or separate radical expressions in a way that may make them easier to understand or calculate.
  • Start by identifying parts of the expression that can be simplified. For cube roots, look for numbers or variables that can be combined or whose cube roots can be easily calculated.
  • Use mathematical rules, such as distributing, factoring, and canceling terms, to assist in the simplification process.
  • Simplifying expressions often requires practice and familiarity with algebraic rules and properties.
This makes it easier to solve the problem or understand the relationship between different elements of an expression.
Radical Expressions
Radical expressions are mathematical expressions that include a radical symbol, \(\sqrt{}\), which signifies taking a root of a number. The type of root is indicated by a small number, called the index, placed just above and to the left of the radical symbol. If no index is shown, it is assumed to be a square root.
Handling radical expressions correctly is crucial because they appear in many areas of mathematics, such as solving equations, integrating functions, and even in geometry when dealing with lengths and distances. The rules for manipulating radical expressions, such as the quotient rule and product rule, are fundamental techniques for working with these expressions.
By applying these rules, you can manage expressions efficiently, helping to achieve a precise and simplified form. This process also aids in systematically solving more complex mathematical problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that the inverse of any linear function \(f(x)=m x+b\), where \(m \neq 0\), is also a linear function. Identify the slope and \(y\)-intercept of the graph of the inverse function in terms of \(m\) and \(b\).

MULTIPLE REPRESENTATIONS The terminal velocity \(v_t\) (in feet per second) of a skydiver who weighs 140 pounds is given by $$ v_t=33.7 \sqrt{\frac{140}{A}} $$ where \(A\) is the cross-sectional surface area (in square feet) of the skydiver. The table shows the terminal velocities (in feet per second) for various surface areas (in square feet) of a skydiver who weighs 165 pounds. \begin{tabular}{|c|c|} \hline Cross-sectional surface area, \(\boldsymbol{A}\) & Terminal velocity, \(\boldsymbol{v}_{\boldsymbol{t}}\) \\ \hline 1 & \(432.9\) \\ 3 & \(249.9\) \\ 5 & \(193.6\) \\ 7 & \(163.6\) \\ \hline \end{tabular} a. Which skydiver has a greater terminal velocity for each value of \(A\) ? b. Describe how the different values of \(A\) given in the table relate to the possible positions of the falling skydiver.

In Exercises 35–46, determine whether the inverse of \(f\) is a function. Then find the inverse. $$ f(x)=x^3-1 $$

Let \(g\) be a horizontal shrink by a factor of \(\frac{2}{3}\), followed by a translation 4 units left of the graph of \(f(x)=\sqrt{6 x}\).

The surface area \(A\) (in square meters) of a person with a mass of 60 kilograms can be approximated by \(A=0.2195 h^{0.3964}\), where \(h\) is the height (in centimeters) of the person. a. Find the inverse function. Then estimate the height of a 60-kilogram person who has a body surface area of \(1.6\) square meters. b. Verify that function \(A\) and the inverse model in part (a) are inverse functions.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free