Chapter 3: Problem 79
Graph the function. Label the vertex, axis of symmetry, and \(x\)-intercepts. \(h(x)=2 x(x-3)\)
Short Answer
Expert verified
The vertex of the function is (1.5, -2.25), the axis of symmetry is \(x=1.5\), and the \(x\)-intercepts are \(x = 0\) and \(x = 3\). See graph for more detail.
Step by step solution
01
Rewrite the function in vertex form
The given quadratic function \(h(x) = 2x(x - 3)\) is currently in factored form. To get it into vertex form, we need to distribute the 2x through the parentheses: \(h(x) = 2x^2 - 6x\).
02
Find the vertex
We can compute this by using the formula \(h = -\frac{b}{2a}\), where \(a = 2\) and \(b = -6\) from the standard form of the quadratic equation \(y = ax^2 + bx + c\). Plugging in these values gives the x-coordinate of the vertex as \(h = -(-6)/2(2) = 1.5\). Determine the y-coordinate of the vertex by substituting \(x = 1.5\) into the function \(h(x)\), giving: \(h(1.5) = 2*(1.5)^2 - 6*(1.5) = -2.25\). So the vertex of the parabola is (1.5, -2.25).
03
Find the axis of symmetry
The equation for the axis of symmetry is \(x = h\), where \(h\) is the x-coordinate of the vertex. So the equation for the axis of symmetry is \(x = 1.5\).
04
Find the x-intercepts
To find the x-intercepts, we set \(h(x) = 0\) and solve for \(x\). The original equation \(h(x) = 2x(x - 3)\) is already factored, which makes this step easier: \(0=2x(x - 3)\). Solving this gives the x-intercepts (roots) as \(x = 0\) and \(x = 3\). Brainstorming these results will confirm our previous steps.
05
Graph the function
Draw a Cartesian coordinate system. Mark the point representing the vertex (1.5, -2.25). Draw a dotted line to represent the axis of symmetry \(x = 1.5\). Mark the two x-intercepts (0,0) and (3,0). Draw a smooth curve to connect these points to form the graph of the function \(h(x) = 2x(x - 3)\). The curve should be a parabola opening upwards, as deduced by our analysis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Form
Quadratic functions can be rewritten in what's known as the "vertex form" to make graphing easier. The vertex form of a quadratic function is given by:
\[h(x) = a(x-h)^2 + k\]where
\[h(x) = a(x-h)^2 + k\]where
- \(a\) represents the coefficient that dictates the direction and width of the parabola.
- \(h\) and \(k\) represent the coordinates of the vertex of the parabola. \((h, k)\) becomes an important point that helps in sketching the graph.
Axis of Symmetry
The axis of symmetry in a quadratic graph is a vertical line that passes through the vertex, effectively dividing the parabola into two mirror-image halves. This concept greatly simplifies graph plotting as it provides clear guidance on how to draw the graph symmetrically.
For any parabola in the form of \(y=ax^2+bx+c\), the axis of symmetry can be found using the formula:
For any parabola in the form of \(y=ax^2+bx+c\), the axis of symmetry can be found using the formula:
- \(x = -\frac{b}{2a}\)
X-Intercepts
X-intercepts are key points where a graph intersects the x-axis, marking the values of \(x\) for which \(h(x)=0\). These points provide crucial insights into the roots of the function and help establish the basic shape of the graph.
For the function \(h(x)=2x(x-3)\), it's already in factored form, making it straightforward to find x-intercepts by setting each factor equal to zero:
For the function \(h(x)=2x(x-3)\), it's already in factored form, making it straightforward to find x-intercepts by setting each factor equal to zero:
- \(2x = 0\) gives \(x=0\)
- \((x-3)=0\) results in \(x=3\)