Chapter 3: Problem 42
Use the Quadratic Formula to write a quadratic equation that has the given solutions.\(x=\frac{15 \pm \sqrt{-215}}{22}\)
Short Answer
Expert verified
The quadratic equation that has the given solutions is \(22x^2 - 15x - \frac{215}{88} = 0\)
Step by step solution
01
Identify the coefficients from the solutions
First, observe the solutions provided, which is \(x = \frac{15 \pm \sqrt{-215}}{22}\). Notice that this is in the form of the quadratic formula, which is \(-\frac{b \pm \sqrt{b^2 - 4ac}}{2a}\). Map the coefficients a, b and c. In this case, \(a = 22\), \(b = -15\), and \(4ac = -215\)
02
Calculate the value of c
Next, calculate the value of c. Using the equation \(4ac = -215\), substitute a into the equation to get \(4*22*c = -215\). Solve for c to get \(c = \frac{-215}{88}\) or \(c = -\frac{215}{88}\)
03
Write the quadratic equation
Lastly, substitute a, b, and c into the general form of a quadratic equation \(ax^2 + bx + c = 0\) to get the quadratic equation. Plug in the obtained coefficients to form the equation: \(22x^2 - 15x - \frac{215}{88} = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation of degree two. It is typically written in the form \(ax^2 + bx + c = 0\), where:
To solve a quadratic equation, one might factor it, complete the square, or, as in our exercise, use the Quadratic Formula. This formula offers a method for finding solutions (or roots) of the quadratic equation, expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula grants solutions both for real and complex solutions, making it a comprehensive tool in solving quadratics.
- \(a\), \(b\), and \(c\) are known as the coefficients of the quadratic equation.
- \(a\) is not equal to zero; otherwise, the equation becomes linear.
To solve a quadratic equation, one might factor it, complete the square, or, as in our exercise, use the Quadratic Formula. This formula offers a method for finding solutions (or roots) of the quadratic equation, expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula grants solutions both for real and complex solutions, making it a comprehensive tool in solving quadratics.
Coefficients in Quadratics
Coefficients are critical components in quadratic equations since they determine the shape and position of the parabola on a graph. In a quadratic equation \(ax^2 + bx + c = 0\), each coefficient plays a distinct role:
From learning how to determine these coefficients, students can gain a deeper understanding of how each element in the equation influences the overarching quadratic graph. This knowledge is essential when conceptualizing the nature of solutions, whether they are real or involve complex numbers.
- \(a\) controls the width and direction of the parabola.
- \(b\) influences the vertex's position along the x-axis.
- \(c\) decides where the parabola intersects the y-axis.
From learning how to determine these coefficients, students can gain a deeper understanding of how each element in the equation influences the overarching quadratic graph. This knowledge is essential when conceptualizing the nature of solutions, whether they are real or involve complex numbers.
Complex Solutions in Quadratics
Complex solutions arise in quadratic equations when the discriminant, \(b^2 - 4ac\), is negative. This results in the square root of a negative number, leading to what we call complex or imaginary numbers. A complex number is expressed as \(a + bi\), where:
- \(a\) is the real part.
- \(bi\) is the imaginary part, with \(i^2 = -1\).