Chapter 10: Problem 28
Evaluate the expression. \({ }_8 C_6\)
Short Answer
Expert verified
The value of \({ }_8 C_6\) is 28.
Step by step solution
01
Substituting the values into the formula
In our problem, we have \(n = 8\) and \(r = 6\). So, \({ }_8 C_6 = \frac{8!}{6!(8-6)!}\). This simplifies to \({ }_8 C_6 = \frac{8!}{6!2!}\)
02
Simplifying the factorials
We can simplify the factorials. The \(8!\) equals to \(8 * 7 * 6 * 5 * 4* 3* 2 * 1\). The \(6!\) equals to \(6 * 5 * 4 * 3 * 2 * 1\). And the \(2!\) is equal to \(2 * 1\). So, \({ }_8 C_6 = \frac{8 * 7 * 6!}{6! * 2* 1}\)
03
Cancelling out similar terms
The \(6!\) in the numerator and the denominator cancels away. So, we are left with \({ }_8 C_6 = 28\).
04
Final Answer
After simplifying the combination, we find that \({ }_8 C_6 = 28\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorials
Factorials are a foundational concept in combinatorics. The factorial of a non-negative integer \(n\) is denoted by \(n!\) and represents the product of all positive integers from 1 to \(n\).
For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\). Factorials grow very quickly as \(n\) increases, which is why simplifying and canceling them in equations is a common practice.
In combinatorial problems, factorials are often used to calculate the total number of ways to arrange or choose items. They form the basis for understanding other concepts such as permutations and combinations.
Factorials can be simplified in expressions to make calculations manageable. For instance, dividing \(8!\) by \(6!\) in the combination formula helps eliminate repetitive terms, simplifying the computation.
For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\). Factorials grow very quickly as \(n\) increases, which is why simplifying and canceling them in equations is a common practice.
In combinatorial problems, factorials are often used to calculate the total number of ways to arrange or choose items. They form the basis for understanding other concepts such as permutations and combinations.
Factorials can be simplified in expressions to make calculations manageable. For instance, dividing \(8!\) by \(6!\) in the combination formula helps eliminate repetitive terms, simplifying the computation.
Combinations
Combinations are ways of selecting items from a larger pool, where the order does not matter. When we calculate combinations, we use the formula \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\), where \(n\) is the total number of items, and \(r\) is the number of items to choose.
This formula helps find how many possible selections there are. For example, \({ }_8 C_6\) means selecting 6 items from a total of 8, disregarding the order.
Combinations focus on selection rather than arrangement, distinguishing them from permutations.
This formula helps find how many possible selections there are. For example, \({ }_8 C_6\) means selecting 6 items from a total of 8, disregarding the order.
Combinations focus on selection rather than arrangement, distinguishing them from permutations.
- Key features of combinations include the ability to choose subsets of a set without repetition.
- In practical scenarios, you might use combinations to figure out lottery odds or to determine the number of ways to form groups from a class.
Permutations
Permutations refer to the arrangements of items where the order is crucial. The formula for calculating permutations of \(r\) items from \(n\) is \(P(n, r) = \frac{n!}{(n-r)!}\).
This calculation gives us the number of different ways \(r\) items can be ordered from a total of \(n\).
Unlike combinations, which deal with selections, permutations consider each specific ordering distinct.
For instance, in permutations, arranging the letters A, B, and C results in different outcomes: ABC, BAC, CAB, etc.
This calculation gives us the number of different ways \(r\) items can be ordered from a total of \(n\).
Unlike combinations, which deal with selections, permutations consider each specific ordering distinct.
For instance, in permutations, arranging the letters A, B, and C results in different outcomes: ABC, BAC, CAB, etc.
- Permutations are essential in situations where arrangement sequence matters, such as in password generation or scheduling.
- Distinguishing between permutations and combinations is vital to solve combinatorial problems accurately.
Binomial Coefficient
The binomial coefficient, usually expressed as \(\binom{n}{r}\), is a mathematical term used to represent the number of ways \(r\) elements can be chosen from \(n\) elements, regardless of the order.
It is a fundamental component of the binomial theorem and appears in the expansion of binomial expressions.
The formula \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\) is used, matching the combinations formula, highlighting that binomial coefficients are the building blocks of combinations.
It is a fundamental component of the binomial theorem and appears in the expansion of binomial expressions.
The formula \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\) is used, matching the combinations formula, highlighting that binomial coefficients are the building blocks of combinations.
- In algebra, binomial coefficients are used in polynomial expansions calculated using Pascal's triangle or directly through the formula.
- They are essential in probability and statistics, often seen in binomial distribution calculations.