Chapter 9: Problem 29
Graph the polar function on the given interval. \(r=3 \sec \theta, \quad(-\pi / 2, \pi / 2)\)
Short Answer
Expert verified
The polar graph of the function is a vertical line at \(x = 3\) in the Cartesian plane.
Step by step solution
01
Understanding the Function
The function given is a polar function expressed as \( r = 3 \sec \theta \), where \( \theta \) is the angle measured from the polar axis. The \( \sec \theta \) is the secant function, which is the reciprocal of the cosine function: \( \sec \theta = \frac{1}{\cos \theta} \).
02
Identify Domain Restrictions
Since \( \sec \theta \) involves \( 1/\cos \theta \), it is undefined where \( \cos \theta = 0 \). Within the interval \((-\pi/2, \pi/2)\), \( \cos \theta \) is never zero, meaning \( \sec \theta \) is defined throughout this domain.
03
Sketch the Function
To sketch, note that for \( \theta = 0 \), \( \cos 0 = 1 \) so \( r = 3 \). As \( \theta \) varies from \(-\pi/2\) to \( \pi/2 \), \( \cos \theta \) changes, causing \( r \) to increase indefinitely as \( \theta \) approaches \(-\pi/2 \) or \( \pi/2 \), since \( \cos \theta \rightarrow 0. \) The curve forms a vertical line at \( x = 3 \) in the Cartesian plane, mapped from polar as \( x = r\cos\theta = 3 \).
04
Converting to Cartesian Coordinates
To confirm our understanding of the polar equation, convert it to Cartesian coordinates. Using \( x = r\cos \theta \) and \( y = r\sin \theta \), substitute \( r = 3 \sec \theta = \frac{3}{\cos \theta} \) into \( x = 3 \), confirming the Cartesian graph is a vertical line at \( x = 3 \). Thus, the polar equation maps onto this vertical line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, notated as \( \sec \theta \), is a trigonometric function that is the reciprocal of cosine. It's defined as \( \sec \theta = \frac{1}{\cos \theta} \). This makes the secant function particularly interesting, because it becomes undefined at points where the cosine function is zero.
- In trigonometry, this means the secant function has vertical asymptotes wherever \( \cos \theta \) equals zero.
- Secant is most often used in problems that involve ratios and projections, such as converting or interpreting growth patterns.
Domain Restrictions
Domain restrictions are limitations on the values a function's input variable can take. For the secant function, \( \sec \theta = \frac{1}{\cos \theta} \), the restriction arises when \( \cos \theta = 0 \) since division by zero is undefined.
- In our given interval \((-\pi/2, \pi/2)\), \( \cos \theta \) never reaches zero. Hence, \( \sec \theta \) is defined everywhere within this range.
- This means there are no places where \( r = 3 \sec \theta \) becomes undefined in this interval. The function \( \sec \theta \) will produce real, calculable values for all given angles \( \theta \) in \((-\pi/2, \pi/2)\).
Conversion to Cartesian Coordinates
To merge the understanding of polar and Cartesian systems, one often converts between them. For a polar equation \( r = 3 \sec \theta \), we convert to Cartesian coordinates using \( x = r\cos \theta \) and \( y = r\sin \theta \).
- First, use \( r = \frac{3}{\cos \theta} \) to replace \( \sec \theta \).
- Input this into \( x = r\cos \theta = 3 \), simplifying the problem to drawing a vertical line in the Cartesian plane at \( x = 3 \).
Graphing Polar Equations
Graphing polar equations translates the mathematical relationships defined by the functions into visual form, offering intuitive insights. With \( r = 3 \sec \theta \), this involves plotting how \( r \) (the radius) changes as \( \theta \) varies.
- At \( \theta = 0 \), \( r = 3 \), this is the starting point on the positive x-axis in polar coordinates.
- As \( \theta \) nears the bounds \(-\pi/2\) or \( \pi/2 \), \( r \) increases indefinitely (tending towards infinity), forming a vertical line in Cartesian terms.