Chapter 8: Problem 25
Determine the convergence of the given series. State the test used; more than one test may be appropriate. $$\sum_{n=1}^{\infty} \frac{n^{2}+4 n-2}{n^{3}+4 n^{2}-3 n+7}$$
Short Answer
Expert verified
The series diverges by the Limit Comparison Test with the harmonic series.
Step by step solution
01
Identify the Type of Series
The given series is \( \sum_{n=1}^{\infty} \frac{n^{2}+4n-2}{n^{3}+4n^{2}-3n+7} \). This series has a rational function in the terms \( a_n = \frac{n^2 + 4n - 2}{n^3 + 4n^2 - 3n + 7} \). We will analyze the degrees of the polynomial in the numerator and denominator to choose a suitable test.
02
Determine the Dominant Terms
For large \( n \), the dominant term in the numerator is \( n^2 \) and in the denominator is \( n^3 \). As \( n \to \infty \), the term \( a_n \approx \frac{n^2}{n^3} = \frac{1}{n} \). This suggests that the series behaves like the harmonic series \( \sum \frac{1}{n} \), which is divergent.
03
Apply the Limit Comparison Test
Use the Limit Comparison Test with \( b_n = \frac{1}{n} \) (the harmonic series). Calculate the limit:\[ \lim_{{n \to \infty}} \frac{a_n}{b_n} = \lim_{{n \to \infty}} n \cdot \frac{n^2+4n-2}{n^3+4n^2-3n+7} = \lim_{{n \to \infty}} \frac{n^3 + 4n^2 - 2n}{n^3 + 4n^2 - 3n + 7} \]Simplifying gives:\[ \lim_{{n \to \infty}} \frac{1 + \frac{4}{n} - \frac{2}{n^2}}{1 + \frac{4}{n} - \frac{3}{n^2} + \frac{7}{n^3}} = 1 \]Since the limit is finite and non-zero, both series either converge or diverge together. Since \( \sum \frac{1}{n} \) diverges, \( \sum a_n \) also diverges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Comparison Test
The Limit Comparison Test is a useful tool in determining the convergence of series, particularly when dealing with rational functions. When you have two series, say \( \sum a_n \) and \( \sum b_n \), you can use this test as follows:
- Calculate \( \lim_{{n \to \infty}} \frac{a_n}{b_n} \).
- If the limit is a positive finite number, then both series will either converge or diverge together.
Rational Functions
A rational function is any function that can be expressed as the ratio of two polynomials. In mathematics, rational functions are often dealt with because they can represent complex relationships easily and are highly applicable across calculus and algebra.
- The numerator is a polynomial of degree \( m \), while the denominator is a polynomial of degree \( n \).
- The behavior of these functions often depends heavily on their degree, meaning the highest powers of \( n \) in the numerator and denominator.
Divergent Series
Series can be categorized as either convergent or divergent, which describes their behavior as more terms are added:
- A convergent series approaches a specific value, meaning it has a finite sum.
- A divergent series, on the other hand, increases indefinitely and does not settle on any specific total.
Dominant Terms
Identifying dominant terms is crucial when analyzing series, particularly those formed by rational functions. The dominant term in a polynomial is the term with the highest power; it influences the series' behavior as \( n \) becomes very large:
- For example, in the polynomial \( n^2 + 4n - 2 \), the dominant term is \( n^2 \), while for \( n^3 + 4n^2 - 3n + 7 \), it's \( n^3 \).
- Dominant terms help simplify complex expressions, enabling us to find approximations like \( \frac{n^2}{n^3} = \frac{1}{n} \).