Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A surface \(\mathcal{S}\) in space is described that cannot be defined in terms of a function \(z=f(x, y)\). Give a parametrization of \(\mathcal{S}\). \(\mathcal{S}\) is the ellipsoid \(\frac{x^{2}}{9}+\frac{y^{2}}{4}+\frac{z^{2}}{16}=1\).

Short Answer

Expert verified
The parametrization of the ellipsoid is \(x(\theta, \phi) = 3\cos(\theta)\sin(\phi),\ y(\theta, \phi) = 2\sin(\theta)\sin(\phi),\ z(\theta, \phi) = 4\cos(\phi)\).

Step by step solution

01

Understand the Ellipsoid Equation

The given ellipsoid is described by the equation \(\frac{x^2}{9} + \frac{y^2}{4} + \frac{z^2}{16} = 1\). This equation represents an ellipsoid centered at the origin. The semi-axes lengths are \(a = 3\), \(b = 2\), and \(c = 4\) for the \(x\), \(y\), and \(z\) dimensions, respectively.
02

Choose a Parametrization Method

For an ellipsoid, a common parametrization involves using spherical coordinates to describe any point on the surface in terms of two parameters, \(\theta\) and \(\phi\). These angles can be related to traditional spherical coordinates.
03

Define the Parametrization Equations

Using parameters \(\theta\) and \(\phi\), where \(\theta\) is the azimuthal angle and \(\phi\) is the polar angle, the parametrization equations for the ellipsoid are:\[x(\theta, \phi) = 3 \cos(\theta) \sin(\phi)\]\[y(\theta, \phi) = 2 \sin(\theta) \sin(\phi)\]\[z(\theta, \phi) = 4 \cos(\phi)\]where \(0 \leq \theta < 2\pi\) and \(0 \leq \phi \leq \pi\). This ensures traversing the entire surface of the ellipsoid.
04

Verify the Parametrization

To verify this parametrization, substitute these expressions for \(x\), \(y\), and \(z\) back into the ellipsoid equation:\[\frac{(3 \cos(\theta) \sin(\phi))^2}{9} + \frac{(2 \sin(\theta) \sin(\phi))^2}{4} + \frac{(4 \cos(\phi))^2}{16} = 1\]Simplifying each term shows that the original equation holds, confirming that the parametrization correctly describes the surface.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ellipsoid
An ellipsoid is a three-dimensional shape that generalizes the form of an ellipse. Much like how an ellipse is a flattened circle, an ellipsoid can be considered as a stretched sphere. More formally, an ellipsoid is defined by an equation of the form:\[\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\]where \(a\), \(b\), and \(c\) are the semi-axis lengths in the \(x\), \(y\), and \(z\) directions, respectively. These values determine the extent of the ellipsoid along each axis. For instance, if all three are equal (i.e., \(a = b = c\)), we have a perfect sphere.In this specific problem, the ellipsoid is centered at the origin with semi-axes of length 3, 2, and 4. It’s important to note that these values influence the shape’s orientation and size. You can think of it as a balloon inflated variably in different directions.
Spherical Coordinates
Spherical coordinates offer a convenient way to describe positions on a sphere or spherical-like surface, such as an ellipsoid. Unlike the traditional Cartesian coordinates (\(x, y, z\)), spherical coordinates use angles and distance:- \(\rho\): The radial distance from the origin- \(\theta\): The azimuthal angle, which rotates around the vertical \(z\)-axis- \(\phi\): The polar angle, measured from the positive \(z\)-axisHowever, when parametrizing an ellipsoid, the distance \(\rho\) is fixed due to the surface's equation, and we focus primarily on the angles \(\theta\) and \(\phi\). By setting these angles, we can traverse any point on the surface:- \(x(\theta, \phi) = a \cos(\theta) \sin(\phi)\)- \(y(\theta, \phi) = b \sin(\theta) \sin(\phi)\)- \(z(\theta, \phi) = c \cos(\phi)\)Here, \(a\), \(b\), and \(c\) represent the semi-axes of the ellipsoid. This conversion lends itself well to complex surface geometry while simplifying calculations.
Surface Equation
The surface equation defines the shape and extent of a surface in mathematical terms. For ellipsoids, the equation connects the coordinate variables \(x, y, z\) through their respective semi-axes:\[\frac{x^2}{9} + \frac{y^2}{4} + \frac{z^2}{16} = 1\]This equation ensures that for any point \((x, y, z)\) on the surface, the relationship outlined is satisfied. The values in the denominators, 9, 4, and 16, are the squares of the semi-axis lengths (3, 2, and 4). This structure maintains the ellipsoid's dimensions.When using a parametrization such as through spherical coordinates, we substitute the parameter relations back into this equation to verify it holds true. If our parametrization is correct, the original surface equation should simplify back to a true statement, thus confirming we have accurately described the surface of the ellipsoid.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free