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Exercises \(21-24\) are designed to challenge your understanding and require no computation. Stokes' Theorem establishes equality between a particular line integral and a particular double integral. What types of circumstances would lead one to choose to evaluate the double integral over the line integral?

Short Answer

Expert verified
Evaluate the double integral if the surface is simpler or if the path is complex.

Step by step solution

01

Understanding Stokes' Theorem

Stokes' Theorem relates a line integral around a closed curve to a surface integral over the surface bounded by the curve. Specifically, it states \( \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (abla \times \mathbf{F}) \cdot d\mathbf{S} \), where \( C \) is the boundary of the surface \( S \). The left side represents the line integral, and the right side represents the double (surface) integral.
02

Circumstances Favoring the Surface Integral

Choosing the surface integral over the line integral is often preferred when the surface \( S \) and the vector field \( \mathbf{F} \) are particularly simple or symmetric in nature. For example, if the vector field \( \mathbf{F} \) is defined in a way that its curl \( abla \times \mathbf{F} \) simplifies the computation of the surface integral, this could be a more straightforward approach.
03

Complexity Considerations

Another consideration is the complexity of the path \( C \). If the path is complex or involves challenging parameterizations, calculating a line integral becomes more cumbersome. If the surface \( S \) allows for easier parametrization or is simple to describe (like a plane or a sphere), solving the double integral can be more straightforward.
04

Evaluating the Environment

Environmental aspects such as continuity and differentiability of \( \mathbf{F} \) over \( S \) can also influence the choice. If the field is well-behaved over the surface but not along the boundary, it might be easier to perform the surface integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Line Integral
A line integral is a fundamental concept in vector calculus, particularly helpful in understanding fields and flows. It involves integrating a function along a curve in a vector field, which can represent diverse physical concepts such as work done by a force or the flow of a fluid. The line integral \(\oint_C \mathbf{F} \cdot d\mathbf{r}\) measures how much a vector field \(\mathbf{F}\) follows a path \(C\).

The "\(\cdot\)" in the integral represents a dot product between the vector field and the infinitesimal curve segment. This helps to determine the component of the field along the curve. Line integrals are essential in Stokes' Theorem, where they relate to the circulation of a vector field around a closed path.
  • If the path \(C\) is complex, solving the line integral might become challenging.
  • Using Stokes' Theorem, we can often simplify problems by changing line integrals into surface integrals.
Surface Integral
A surface integral, present on the right side of Stokes' Theorem, involves integrating over a surface to find a cumulative property, like flux through the surface. It's akin to adding up changes over a surface area defined in a three-dimensional space.

Unlike line integrals, which accumulate a function along a path, surface integrals consider all area elements on a surface. In mathematical terms, we express this as \(\iint_S (abla \times \mathbf{F}) \cdot d\mathbf{S}\). The expression \((abla \times \mathbf{F})\) refers to the curl of the vector field, which measures the field's rotation around a point.

Surface integrals often allow complex problems to become straightforward through the use of symmetry or by utilizing simple surface descriptions, making them easier when the vector field and surface are uncomplicated.
  • Symmetrical or simple surfaces lend themselves to easier computation via surface integrals.
  • They can simplify calculations for flows or fields passing through surfaces, as compared to complex paths.
Vector Field
A vector field is a representation of a vector quantity related to every point in a region of space. It often visualizes phenomena like fluid flow, electromagnetic fields, and force fields. In mathematical notation, a vector field is commonly described as \(\mathbf{F}(x, y, z) = P(x, y, z)\hat{i} + Q(x, y, z)\hat{j} + R(x, y, z)\hat{k}\), indicating directional components at each point in space.

In the context of Stokes' Theorem, the vector field \(\mathbf{F}\) serves as the basis for computing integrals around curves or over surfaces. Understanding its properties like curl and divergence is crucial in determining how it behaves with regard to Stokes' Theorem.
  • The curl of a vector field helps to measure rotation or swirling strength around a point, playing a crucial role in surface integrals.
  • Analyzing vector fields assists in choosing whether to compute line or surface integrals for a given problem.
Double Integral
A double integral extends the concept of integration to functions of two variables, often used to calculate volume under a surface in space. In the realm of Stokes' Theorem, it converts line integrals into an evaluation over the surface area, making it a staple in dealing with shapes and volumes.

Through double integrals, we compute surface integrals by summing values over infinitesimal pieces of a surface. This method is particularly advantageous when dealing with functions defined across a surface, turning complex line integrals into manageable computations depending on the surface's simplicity.
  • Double integrals help to transition from line integrals along closed paths to evaluation across surfaces.
  • They simplify complex vector fields into integrals over comprehensive, often symmetrical, surfaces.

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Most popular questions from this chapter

When computing flux, what does it mean when the result is a negative number?

Parametrize the surface defined by the function \(z=f(x, y)\) over each of the given regions \(R\) of the \(x\) -y plane. \(z=4 x+2 y^{2}\) (a) \(R\) is the rectangle bounded by \(1 \leq x \leq 4\) and \(5 \leq y \leq 7\) (b) \(R\) is the ellipse with major axis of length 8 parallel to the \(x\) -axis, and minor axis of length 6 parallel to the \(y\) -axis, centered at the origin. (c) \(R\) is the triangle with vertices (0,0),(2,2) and (0,4) . (d) \(R\) is the annulus bounded between the circles, centered at the origin, with radius 2 and radius 5 .

In Exercises \(17-20\), a conservative vector field \(\vec{F}\) and a curve C are given. 1\. Find a potential function \(f\) for \(\vec{F}\) 2\. Compute curl \(\vec{F}\). 3\. Evaluate \(\int_{C} \vec{F} \cdot d \vec{r}\) directly, i.e., using Key Idea 14.3.1. 4\. Evaluate \(\int_{C} \vec{F} \cdot d \vec{r}\) using the Fundamental Theorem of Line Integrals. $$ \begin{array}{l} \vec{F}=\left\langle 2 x y z, x^{2} z, x^{2} y\right\rangle, c \text { is curve parametrized by } \vec{r}(t)= \\ \langle 2 t+1,3 t-1, t\rangle \text { on } 0 \leq t \leq 2 \end{array} $$

A domain \(D\) in space is given. Parametrize each of the bounding surfaces of \(D\). \(D\) is the domain bounded by \(z=2 y, y=4-x^{2}\) and \(z=0\).

In Exercises \(17-20\), a conservative vector field \(\vec{F}\) and a curve C are given. 1\. Find a potential function \(f\) for \(\vec{F}\) 2\. Compute curl \(\vec{F}\). 3\. Evaluate \(\int_{C} \vec{F} \cdot d \vec{r}\) directly, i.e., using Key Idea 14.3.1. 4\. Evaluate \(\int_{C} \vec{F} \cdot d \vec{r}\) using the Fundamental Theorem of Line Integrals. $$ \begin{aligned} &\vec{F}=(2 x+y, 2 y+x), C \text { is curve parametrized by } \vec{r}(t)=\\\ &\left\langle t^{2}-t, t^{3}-t\right) \text { on } 0 \leq t \leq 1 \end{aligned} $$

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