Chapter 13: Problem 5
Why do \(z=f(x, y)\) and \(z=g(x, y)=f(x, y)+h,\) for some real number \(h\), have the same surface area over a region \(R ?\)
Short Answer
Expert verified
The surface areas are the same because adding a constant \( h \) does not affect partial derivatives.
Step by step solution
01
Understanding the Problem
We have two functions: \( z = f(x, y) \) and \( z = g(x, y) = f(x, y) + h \), where \( h \) is a constant. Both need to be evaluated over a region \( R \). We are asked to compare their surface areas.
02
Recall Surface Area Formula
The formula for the surface area of \( z = f(x, y) \) over a region \( R \) is given by: \[ A = \iint_R \sqrt{1 + \left( \frac{\partial f}{\partial x} \right)^2 + \left( \frac{\partial f}{\partial y} \right)^2} \, dx \, dy \]
03
Apply the Formula to Each Function
For \( z=g(x, y) = f(x, y) + h \), calculate the partial derivatives with respect to \( x \) and \( y \):\( \frac{\partial g}{\partial x} = \frac{\partial f}{\partial x} \) and \( \frac{\partial g}{\partial y} = \frac{\partial f}{\partial y} \). The surface area formula for \( g(x, y) \) becomes: \[ \iint_R \sqrt{1 + \left( \frac{\partial g}{\partial x} \right)^2 + \left( \frac{\partial g}{\partial y} \right)^2} \, dx \, dy \]
04
Comparing the Two Surface Area Formulas
The expressions \( \sqrt{1 + \left( \frac{\partial f}{\partial x} \right)^2 + \left( \frac{\partial f}{\partial y} \right)^2} \) and \( \sqrt{1 + \left( \frac{\partial g}{\partial x} \right)^2 + \left( \frac{\partial g}{\partial y} \right)^2} \) are identical since partial derivatives do not change when adding a constant.Therefore, the surface areas of \( f \) and \( g \) over \( R \) are the same.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
When dealing with functions of multiple variables, partial derivatives help us understand how a function changes with respect to one variable while keeping the others constant. For a function \(z = f(x, y)\), the partial derivative with respect to \(x\), denoted \(\frac{\partial f}{\partial x}\), represents the rate of change of \(f\) as \(x\) changes and \(y\) remains fixed. Similarly, the partial derivative with respect to \(y\), \(\frac{\partial f}{\partial y}\), shows how \(f\) changes as \(y\) increases while \(x\) is constant.
- Partial derivatives are crucial when calculating the surface area of a function, as they provide the slopes needed in the surface area formula.
- In the context of surface area, they help determine the orientation and steepness of the surface, affecting the area computation.
Double Integrals
Double integrals extend the concept of integration to functions of multiple variables, allowing us to compute accumulated quantities over a region. In the case of surface area, a double integral helps sum up all the infinitesimal pieces of surface area over the region \(R\). If \(A\) represents surface area, it is computed as:\[ A = \iint_R \sqrt{1 + \left( \frac{\partial f}{\partial x} \right)^2 + \left( \frac{\partial f}{\partial y} \right)^2} \, dx \, dy \]
- The double integral essentially covers region \(R\), aggregating all tiny surface areas influenced by the partial derivatives of the function.
- It allows for a full accumulation over not just linear paths, but entire regions defined by two variables.
Constant Function Addition
Adding a constant to a function, such as changing \(z = f(x, y)\) to \(z = g(x, y) = f(x, y) + h\), is straightforward in theory but requires understanding its implications in calculus.
- This constant \(h\) represents a vertical shift in the graph of the function, altering its position without changing its shape or the nature of its surface.
- The key takeaway is that since this shift does not affect the function's partial derivatives, the geometric properties essential for surface area calculation remain unchanged.