Chapter 11: Problem 5
Describe a scenario where an object's average speed is a large number, but the magnitude of the average velocity is not a large number.
Short Answer
Expert verified
A car running in circles at high speed has a large average speed but a small average velocity.
Step by step solution
01
Understanding Speed and Velocity
First, recall the definitions:
- Speed is a scalar quantity representing how fast an object travels over a distance in a given period, without considering direction.
- Velocity is a vector quantity that includes both speed and direction. Average velocity is the total displacement divided by the total time. Thus, it's possible for an object to travel a great distance (large average speed) but end up near its starting point (small displacement, thus small average velocity).
02
Choosing the Scenario - Circular Track
Imagine a car moving in a circular track with a radius of 100 meters. The car completes 10 laps in 1000 seconds. Each lap covers a circumferential distance of approximately 628.3 meters. This illustrates how substantial distance is covered over time, but the initial and final positions are the same or very close, making displacement very small or almost zero.
03
Calculating Average Speed
The average speed is calculated by taking the total distance traveled and dividing by the time taken. Here, the total distance is 10 laps × 628.3 meters/lap = 6283 meters. The time taken is 1000 seconds. Thus, the average speed is:\[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{6283 \text{ meters}}{1000 \text{ seconds}} = 6.283 \text{ m/s}\]
04
Calculating Average Velocity
Average velocity is found by dividing the total displacement by the total time. Since the car ends its motion very close to the starting point after 10 laps, the total displacement is approximately zero. Hence, the average velocity is:\[\text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} \approx \frac{0 \text{ meters}}{1000 \text{ seconds}} = 0 \text{ m/s}\]
05
Comparing Both Quantities
The scenario depicts a high average speed due to the large distance covered, while the average velocity is negligible because the net change in position is small. This effectively illustrates how average speed can be large even when average velocity is not, due to the path taken by the object.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Scalar and Vector Quantities
Understanding the difference between scalar and vector quantities is fundamental in physics. Scalars are quantities that are described only by magnitude. They do not have a direction. Common examples include:
- Speed
- Distance
- Time
- Mass
Circular Motion
Circular motion is a fascinating concept in physics that offers insights into how objects move along a circular path. It's essential to note that while an object moving in a circle at constant speed has uniform circular motion, its velocity is actually not constant. This is because velocity is a vector, and its direction is always changing even if the speed remains the same. For instance, consider a car traveling on a circular track:
- The car's speed might be steady, but its direction changes continuously as it moves around the track.
- This means the car is undergoing continuous acceleration despite moving at constant speed.
Displacement and Distance
In physics, distance and displacement are two crucial concepts often confused. Distance refers to the total path length traveled by an object, ignoring its starting and finishing positions. It's a scalar quantity, meaning only magnitude is considered.
Displacement, however, is a vector quantity. It represents the change in position of an object and considers the straight line distance from start to finish, taking direction into account. This is why in our circular motion example, although the car travels a considerable distance, its displacement after a full circuit is almost zero. Understanding these differences is crucial for solving motion analysis problems where path and position must be considered.
Displacement, however, is a vector quantity. It represents the change in position of an object and considers the straight line distance from start to finish, taking direction into account. This is why in our circular motion example, although the car travels a considerable distance, its displacement after a full circuit is almost zero. Understanding these differences is crucial for solving motion analysis problems where path and position must be considered.
Physics Problems
Physics problems, particularly those related to motion, often require comprehensive understanding of the relationships between different physical quantities. By breaking down problems into smaller, understandable parts, students can effectively tackle even complex scenarios. Common tips that can help include:
- Identifying what quantities are given and what needs to be found.
- Diagrams can help visualize scenarios, especially in problems involving vectors and motion.
- Reviewing equations and understanding their derivations to apply them correctly.
Motion Analysis
Motion analysis involves dissecting how objects move from one point to another and is fundamental in physics. This analysis includes understanding various physical quantities and how they relate:
- Speed and velocity: Even if an object moves rapidly over a long period, its velocity can still be low if it returns to its start point.
- Acceleration: Crucial in scenarios where velocity changes, such as in circular motion.
- Graphs and equations are useful tools for visualizing and predicting motion patterns.