Chapter 11: Problem 10
Sketch the vector-valued function on the given interval. $$ \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle, \text { on }[0,2] $$
Short Answer
Expert verified
The function describes an ellipse traced by \( \vec{r}(t) \) on \([0,2]\).
Step by step solution
01
Understand the Function
The vector-valued function \( \vec{r}(t) = \langle 3 \sin(\pi t), 2 \cos(\pi t) \rangle \) describes a parametric curve in the plane. The parameter \( t \) varies from 0 to 2.
02
Determine Key Points
Evaluate the vector function at key values of \( t \) to understand the curve's behavior. Find \( \vec{r}(0), \vec{r}(1), \vec{r}(2) \). Each of these key values represents specific points on the curve.
03
Calculate \(\vec{r}(0)\)
Substitute \( t = 0 \) into the function: \( \vec{r}(0) = \langle 3 \sin(0), 2 \cos(0) \rangle = \langle 0, 2 \rangle \). This is the starting point of the curve.
04
Calculate \(\vec{r}(1)\)
Substitute \( t = 1 \) into the function: \( \vec{r}(1) = \langle 3 \sin(\pi), 2 \cos(\pi) \rangle = \langle 0, -2 \rangle \). This point is vertically below the starting point.
05
Calculate \(\vec{r}(2)\)
Substitute \( t = 2 \) into the function: \( \vec{r}(2) = \langle 3 \sin(2\pi), 2 \cos(2\pi) \rangle = \langle 0, 2 \rangle \). This shows that the curve returns to the starting point, completing a cycle.
06
Sketch the Curve
Plot the calculated points \( \langle 0, 2 \rangle \), \( \langle 0, -2 \rangle \) on a graph, and visualize the transition between these points using the periodic nature of sine and cosine, which completes an ellipse. The range of \( \vec{r}(t) \) will form an ellipse centered at the origin with semi-major axis 3 on the X-axis and semi-minor axis 2 on the Y-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Curves
Parametric curves are a way to represent curves using parameters rather than traditional Cartesian coordinates. Here, each coordinate of the curve is expressed as a function of one variable, usually denoted as \( t \). This approach is flexible because it allows us to describe more complex shapes that might not be easily represented by simple algebraic equations.
In the case of the vector-valued function \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), both the \( x \)-coordinate and \( y \)-coordinate are controlled by the same parameter \( t \) as it varies from 0 to 2.
In the case of the vector-valued function \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), both the \( x \)-coordinate and \( y \)-coordinate are controlled by the same parameter \( t \) as it varies from 0 to 2.
- The sine function affects the \( x \)-position while the cosine function affects the \( y \)-position.
- This description lays out a path or trajectory traced out as \( t \) changes.
Ellipses
An ellipse is a type of conic section that forms when a plane intersects a cone at an angle. It's a symmetrical shape resembling an elongated circle.
With the vector-valued function given, \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), we can identify the figure described in the plane as an ellipse. Why is this so?
With the vector-valued function given, \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), we can identify the figure described in the plane as an ellipse. Why is this so?
- The coefficients in front of the sine and cosine functions determine the axes lengths of the ellipse.
- The coefficient 3 in \( 3 \sin(\pi t) \) indicates the length of the semi-major axis along the \( x \)-axis.
- Similarly, the coefficient 2 in \( 2 \cos(\pi t) \) corresponds to the semi-minor axis along the \( y \)-axis.
Sine and Cosine Functions
Sine and cosine are fundamental trigonometric functions that describe rotational and oscillatory motion.
For the function \( \vec{r}(t) = \langle 3 \sin(\pi t), 2 \cos(\pi t) \rangle \), both functions guide the trajectory of the parametric curve. Here's why these functions are key:
For the function \( \vec{r}(t) = \langle 3 \sin(\pi t), 2 \cos(\pi t) \rangle \), both functions guide the trajectory of the parametric curve. Here's why these functions are key:
- The \( \sin(\pi t) \) component affects movement along the \( x \)-axis. Its periodic nature cycles through values from -3 to 3.
- The \( \cos(\pi t) \) component dictates the \( y \)-axis movement, repeating its cycle from -2 to 2.
Calculating Key Points
Calculating key points involves evaluating the vector function at specific values of \( t \). This helps us understand important characteristics of the curve.
For the ellipse prescribed by \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), compute vital positions:
For the ellipse prescribed by \( \vec{r}(t)=\langle 3 \sin (\pi t), 2 \cos (\pi t)\rangle \), compute vital positions:
- At \( t = 0 \), \( \vec{r}(0) = \langle 0, 2 \rangle \).
- At \( t = 1 \), \( \vec{r}(1) = \langle 0, -2 \rangle \).
- At \( t = 2 \), \( \vec{r}(2) = \langle 0, 2 \rangle \).