Chapter 10: Problem 27
In Exercises 27-30, find the given distances. The distance from the point (1,2,3) to the plane \(3(x-1)+(y-2)+5(z-2)=0\)
Short Answer
Expert verified
The distance is \(\frac{\sqrt{35}}{7}\).
Step by step solution
01
Identify the Problem
We need to find the distance from a point to a plane in space. The point given is \((1, 2, 3)\), and the plane is described by the equation \(3(x-1)+(y-2)+5(z-2)=0\).
02
Simplify the Plane Equation
First, we rewrite the given plane equation in the standard form. Expanding \(3(x-1) + (y-2) + 5(z-2) = 0\) gives us:\[ 3x - 3 + y - 2 + 5z - 10 = 0 \]Combine like terms to obtain the equation:\[ 3x + y + 5z = 15 \]
03
Use the Distance Formula
The formula to find the distance \(D\) from a point \((x_1, y_1, z_1)\) to a plane \(Ax + By + Cz + D = 0\) is given by:\[ D = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]For our plane, \(A = 3\), \(B = 1\), \(C = 5\), and after rearranging \(15\) to the right, \(D = -15\). The point is \((x_1, y_1, z_1) = (1, 2, 3)\).
04
Plug In the Values
Now, substitute the values into the formula:\[ D = \frac{|3(1) + 1(2) + 5(3) - 15|}{\sqrt{3^2 + 1^2 + 5^2}} \]Simplifying the numerator, we have:\[ |3 + 2 + 15 - 15| = |5| = 5 \]And simplifying the denominator:\[ \sqrt{3^2 + 1^2 + 5^2} = \sqrt{9 + 1 + 25} = \sqrt{35} \]
05
Calculate the Distance
Now calculate the distance:\[ D = \frac{5}{\sqrt{35}} \]To simplify, multiply numerator and denominator by \(\sqrt{35}\):\[ D = \frac{5\sqrt{35}}{35} = \frac{\sqrt{35}}{7} \]
06
Provide the Final Answer
The distance from the point \((1, 2, 3)\) to the plane \(3x + y + 5z = 15\) is \(\frac{\sqrt{35}}{7}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Distance Formula
To find the shortest distance between a point and a plane in 3D space, we use a specific distance formula. This formula helps to determine how "far away" a point is from a flat surface, like a plane, which is crucial in many geometric applications.
The formula is:
It ensures accurate calculations of distances in numerous fields such as physics, engineering, and architecture.
The formula is:
- \[ D = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]
- In this equation,
- \(A\), \(B\), and \(C\) are the coefficients from the plane's equation \(Ax + By + Cz + D = 0\).
- \(x_1\), \(y_1\), \(z_1\) represent the coordinates of the point from which we measure the distance.
It ensures accurate calculations of distances in numerous fields such as physics, engineering, and architecture.
Plane Equation
A plane in 3D geometry represents a flat, level surface that can extend infinitely in two dimensions. The standard form of a plane's equation is:
The coefficients \(A\), \(B\), and \(C\) describe the orientation of the plane in space. For example, in our case:
- \[ Ax + By + Cz + D = 0 \]
The coefficients \(A\), \(B\), and \(C\) describe the orientation of the plane in space. For example, in our case:
- The equation \(3x + y + 5z = 15\) implies a plane tilted towards the direction influenced by these coefficients in a three-dimensional system.
- The constant \(D\) affects where the plane crosses the axes in the 3D space.
3D Geometry
3D geometry, or three-dimensional geometry, is the field of mathematics dealing with figures that have length, width, and height.
This contrasts with 2D geometry, which only involves length and width.
Concepts like planes and vectors are much more complex as they operate in an extra dimension. Understanding these aspects is crucial for visualizing and solving real-world problems where depth plays a significant role, such as in computer graphics and engineering fields.
This contrasts with 2D geometry, which only involves length and width.
- In 3D geometry, we define shapes like cubes, spheres, planes, and more, all of which have an added depth dimension compared to their 2D counterparts.
- Coordinate systems, like the cartesian coordinates \((x, y, z)\), play a vital role in describing positions within this space.
Concepts like planes and vectors are much more complex as they operate in an extra dimension. Understanding these aspects is crucial for visualizing and solving real-world problems where depth plays a significant role, such as in computer graphics and engineering fields.
Vector Mathematics
Vector mathematics is a field of mathematics dealing with quantities having both magnitude and direction. Vectors are essential in 3D geometry, as they help describe directions and positions.
This concept is fundamental when calculating distances or angles.
Vector operations, like addition, subtraction, and cross-products, offer techniques to solve geometric problems, making them integral in fields like physics and computer science.
- For example, a vector's magnitude might represent a force, while its direction indicates where this force is applied.
- Vectors are usually represented as \((a, b, c)\), showing their direction and magnitude in three-dimensional space.
This concept is fundamental when calculating distances or angles.
Vector operations, like addition, subtraction, and cross-products, offer techniques to solve geometric problems, making them integral in fields like physics and computer science.