Chapter 10: Problem 19
Find \(\|\vec{u}\|,\|\vec{v}\|,\|\vec{u}+\vec{v}\|\) and \(\|\vec{u}-\vec{v}\|\) \(\vec{u}=\langle 1,2\rangle, \quad \vec{v}=\langle-3,-6\rangle\)
Short Answer
Expert verified
\(\|\vec{u}\| = \sqrt{5}\), \(\|\vec{v}\| = 3\sqrt{5}\), \(\|\vec{u} + \vec{v}\| = 2\sqrt{5}\), \(\|\vec{u} - \vec{v}\| = 4\sqrt{5}\).
Step by step solution
01
Calculate the Magnitude of \(\vec{u}\)
The magnitude of a vector \(\vec{u} = \langle a, b \rangle\) is given by the formula \(\|\vec{u}\| = \sqrt{a^2 + b^2}\). For \(\vec{u} = \langle 1, 2 \rangle\), substitute the values: \(\|\vec{u}\| = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}\).
02
Calculate the Magnitude of \(\vec{v}\)
The magnitude of vector \(\vec{v} = \langle -3, -6 \rangle\) is found using the same formula. Substitute \(a = -3\) and \(b = -6\): \(\|\vec{v}\| = \sqrt{(-3)^2 + (-6)^2} = \sqrt{9 + 36} = \sqrt{45} = 3\sqrt{5}\).
03
Add the Vectors \(\vec{u}\) and \(\vec{v}\)
To add vectors \(\vec{u} = \langle 1, 2 \rangle\) and \(\vec{v} = \langle -3, -6 \rangle\), add corresponding components: \(\vec{u} + \vec{v} = \langle 1 + (-3), 2 + (-6) \rangle = \langle -2, -4 \rangle\).
04
Calculate the Magnitude of \(\vec{u} + \vec{v}\)
Calculate the magnitude of the resultant vector \(\langle -2, -4 \rangle\): \(\|\vec{u} + \vec{v}\| = \sqrt{(-2)^2 + (-4)^2} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5}\).
05
Subtract the Vectors \(\vec{u}\) and \(\vec{v}\)
To subtract vector \(\vec{v}\) from \(\vec{u}\), subtract the corresponding components: \(\vec{u} - \vec{v} = \langle 1 - (-3), 2 - (-6) \rangle = \langle 4, 8 \rangle\).
06
Calculate the Magnitude of \(\vec{u} - \vec{v}\)
Calculate the magnitude of the vector \(\langle 4, 8 \rangle\): \(\|\vec{u} - \vec{v}\| = \sqrt{4^2 + 8^2} = \sqrt{16 + 64} = \sqrt{80} = 4\sqrt{5}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
Vector addition is a fundamental operation in which we join two or more vectors to get a resultant vector. Each vector has a magnitude and direction. In 2D space, like in our example, we represent vectors with components in the x and y directions. To add vectors, you simply add their corresponding components together.
For instance, if we have vectors \( \vec{u} = \langle 1, 2 \rangle \) and \( \vec{v} = \langle -3, -6 \rangle \), the sum is:
For instance, if we have vectors \( \vec{u} = \langle 1, 2 \rangle \) and \( \vec{v} = \langle -3, -6 \rangle \), the sum is:
- Add the x-components: \(1 + (-3) = -2\)
- Add the y-components: \(2 + (-6) = -4\)
Vector Subtraction
Just like addition, vector subtraction involves combining vectors, but in a different manner. It consists of taking one vector away from another by subtracting their corresponding components.
When subtracting \( \vec{v} \) from \( \vec{u} \), we perform the following operations:
When subtracting \( \vec{v} \) from \( \vec{u} \), we perform the following operations:
- Subtract the x-components: \(1 - (-3) = 4\)
- Subtract the y-components: \(2 - (-6) = 8\)
Euclidean Norm
The Euclidean norm (or magnitude) of a vector provides a measure of its length or size. For a vector \( \vec{a} = \langle a_1, a_2 \rangle \), its magnitude is calculated using the formula:\[\|\vec{a}\| = \sqrt{a_1^2 + a_2^2}\]
This formula is grounded in the Pythagorean theorem, viewing the vector as the hypotenuse of a right triangle.
In our example:
This formula is grounded in the Pythagorean theorem, viewing the vector as the hypotenuse of a right triangle.
In our example:
- For \( \vec{u} = \langle 1, 2 \rangle \), \( \|\vec{u}\| = \sqrt{1^2 + 2^2} = \sqrt{5} \)
- For \( \vec{v} = \langle -3, -6 \rangle \), \( \|\vec{v}\| = \sqrt{9 + 36} = 3\sqrt{5} \)
- For \( \vec{u} + \vec{v} = \langle -2, -4 \rangle \), \( \|\vec{u} + \vec{v}\| = \sqrt{20} = 2\sqrt{5} \)
- For \( \vec{u} - \vec{v} = \langle 4, 8 \rangle \), \( \|\vec{u} - \vec{v}\| = \sqrt{80} = 4\sqrt{5} \)
Vector Operations
Vector operations, which include addition, subtraction, and calculation of magnitudes, are crucial for analyzing physical phenomena in physics, engineering, and mathematics. These operations allow us to manipulate vectors to determine resultant forces, directions, or velocities among others.
When combining vectors, both the magnitude and direction are important:
When combining vectors, both the magnitude and direction are important:
- **Addition**: Combines directions and magnitudes.
- **Subtraction**: Presents the change or difference between two vectors.
- **Magnitude**: Gives the length, helping understand the vector's strength or speed.