Chapter 1: Problem 1
What are the three ways in which a limit may fail to exist?
Short Answer
Expert verified
Limits may fail to exist due to infinite oscillation, unbounded behavior, or differing left and right limits.
Step by step solution
01
Identify Conceptual Overview
Limits in calculus help us understand the value that a function approaches as the input approaches a certain point. Sometimes, limits do not exist, and there are three main types of failures.
02
Understand Infinite Oscillation
A limit does not exist when a function oscillates infinitely as the input approaches a certain point. An example is the function \( f(x) = \sin\left(\frac{1}{x}\right) \) as \( x \) approaches 0; the function keeps oscillating between 1 and -1, never settling towards a single value.
03
Recognize Unbounded Behavior
Another way a limit can fail to exist is when the function becomes unbounded, meaning it goes to infinity or negative infinity as the input approaches a certain value. For example, \( \lim_{{x \to 0}} \frac{1}{x^2} = \infty \), indicating the function heads towards infinity and thus the limit does not exist.
04
Different Left and Right Limits
A limit does not exist when the left-hand limit is different from the right-hand limit. For instance, with the piecewise function \( f(x) = \begin{cases} x^2 & \text{if } x < 0 \ x + 1 & \text{if } x \geq 0 \end{cases} \), approaching from left yields a limit of 0, and from the right yields a limit of 1 at \( x = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Infinite Oscillation
In calculus, a limit might not exist when a function experiences what's called infinite oscillation. This happens when a function doesn't settle at any single value as the input gets close to a certain point. The function continually jumps between values, like a spinning top that never stops.
An illustrative example of this concept is the function \( f(x) = \sin\left(\frac{1}{x}\right) \) as \( x \) approaches zero. As \( x \) gets closer to 0, the value of \( \frac{1}{x} \) becomes very large, leading to the sine function oscillating wildly between 1 and -1, infinitely and rapidly.
An illustrative example of this concept is the function \( f(x) = \sin\left(\frac{1}{x}\right) \) as \( x \) approaches zero. As \( x \) gets closer to 0, the value of \( \frac{1}{x} \) becomes very large, leading to the sine function oscillating wildly between 1 and -1, infinitely and rapidly.
- Such oscillations prevent the function from approaching any particular value.
- The limit does not exist as there is no predictable outcome.
Unbounded Behavior
Unbounded behavior is another significant reason why a limit may fail to exist in calculus. When a function's value becomes exceedingly large, either positive or negative, as it approaches a specific point, it's said to be unbounded. This means that the function is racing off to infinity or negative infinity and never settles to a finite number.
Take for instance the expression \( \lim_{{x \to 0}} \frac{1}{x^2} \). As \( x \) gets closer to zero, \( \frac{1}{x^2} \) skyrockets to positive infinity. The values increase without bound, showing unbounded behavior.
Take for instance the expression \( \lim_{{x \to 0}} \frac{1}{x^2} \). As \( x \) gets closer to zero, \( \frac{1}{x^2} \) skyrockets to positive infinity. The values increase without bound, showing unbounded behavior.
- This limitless growth means there's no specific number the function is tending towards.
- In such cases, the limit does not exist due to the function's runaway nature.
Left and Right Limits
One more way a limit may not exist is when there is a discrepancy between left and right limits. A limit only exists if both these directional limits meet at the same endpoint. If they differ, no single limit exists for that point.
Consider the piecewise function \( f(x) = \begin{cases} x^2 & \text{if } x < 0 \ x + 1 & \text{if } x \geq 0 \end{cases} \). As \( x \) approaches zero, coming from the left side (\( x < 0 \)), the function heads towards 0, whereas from the right side (\( x \geq 0 \)), it approaches 1.
Consider the piecewise function \( f(x) = \begin{cases} x^2 & \text{if } x < 0 \ x + 1 & \text{if } x \geq 0 \end{cases} \). As \( x \) approaches zero, coming from the left side (\( x < 0 \)), the function heads towards 0, whereas from the right side (\( x \geq 0 \)), it approaches 1.
- The left-hand limit results in 0, while the right-hand limit results in 1.
- Since these limits do not match, the overall limit at \( x = 0 \) does not exist.