Chapter 2: Problem 25
Find the normalizer of the indicated subgroup in the indicated group. $$ \langle\mathrm{j}\rangle \text { in } Q_{8} $$
Short Answer
Expert verified
The normalizer of \( \langle j \rangle \) in \( Q_8 \) is \( \{ 1, -1, j, -j \} \).
Step by step solution
01
Understand the Quaternion Group
The quaternion group, denoted as \( Q_8 \), is the group \( \{ 1, -1, i, -i, j, -j, k, -k \} \) with the multiplication rules \( i^2 = j^2 = k^2 = ijk = -1 \). It is a non-abelian group of order 8.
02
Define Subgroup \( \langle j \rangle \)
The subgroup \( \langle j \rangle \) is generated by the element \( j \) from \( Q_8 \). Since \( j^2 = -1 \), the subgroup \( \langle j \rangle \) contains the elements \( \{ 1, j, -1, -j \} \).
03
Define the Normalizer
The normalizer of a subgroup \( H \) in a group \( G \), denoted by \( N_G(H) \), is the set of elements in \( G \) that conjugate \( H \) into itself. Formally, \( N_G(H) = \{ g \in G \mid gHg^{-1} = H \} \).
04
Find Conjugates in \( Q_8 \)
Conjugating element \( j \) by another element \( g \in Q_8 \) requires finding \( gjg^{-1} \). Compute for each element: - For \( 1 \) and \( -1 \): \( 1j1^{-1} = j \), \( (-1)j(-1)^{-1} = j \).- For \( i, -i \): \( iji^{-1} = -j \), \( (-i)j(-i)^{-1} = -j \).- For \( j, -j \): \( jjj^{-1} = j \), \( (-j)j(-j)^{-1} = j \).- For \( k, -k \): \( kjk^{-1} = -j \), \( (-k)j(-k)^{-1} = -j \).
05
Determine the Normalizer
Based on calculations, those elements from \( Q_8 \) for which \( gjg^{-1} \) results in elements of \( \langle j \rangle \) (i.e., \( j \) or \( -j \)) are \( N_{Q_8}(\langle j \rangle) = \{ 1, -1, j, -j \} \).
06
Validate Normalizer Contains Subgroup
We confirm that the normalizer \( N_{Q_8}(\langle j \rangle) \) properly contains the subgroup \( \langle j \rangle = \{ 1, j, -1, -j \} \), as all elements in \( \langle j \rangle \) conjugate \( j \) to other elements in \( \langle j \rangle \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quaternion Group
The Quaternion group, often denoted by \( Q_8 \), is an essential concept in group theory, specifically in the study of non-abelian groups. It comprises eight elements: \( \{ 1, -1, i, -i, j, -j, k, -k \} \). These elements follow specific multiplication rules:
- \( i^2 = j^2 = k^2 = -1 \)
- \( ijk = -1 \)
Group Theory
Group theory is a branch of mathematics that studies groups, which are sets equipped with an operation that combines any two elements to form a third element within the set, subject to four main properties: closure, associativity, identity, and invertibility. Here's a quick rundown:
- Closure: For any elements \( a \) and \( b \) in the group, the result of the operation, \( a \ast b \), is also in the group.
- Associativity: For any elements \( a, b, \) and \( c \) in the group, \((a \ast b) \ast c = a \ast (b \ast c)\).
- Identity Element: There is an element \( e \) in the group such that for any element \( a \) in the group, \( e \ast a = a \ast e = a \).
- Inverse: For each element \( a \) in the group, there is an element \( b \) in the group such that \( a \ast b = b \ast a = e \).
Normalizer
The concept of a normalizer within group theory is particularly intriguing, and it refers to the set of elements in a group that keeps a given subgroup invariant under conjugation. Formally, for a subgroup \( H \) of a group \( G \), the normalizer, denoted \( N_G(H) \), includes elements \( g \) in \( G \) such that: \[ gHg^{-1} = H \]
- This means that when you conjugate each element of the subgroup by some fixed element \( g \), you end up with the subgroup itself.
- The normalizer is always a subgroup of \( G \) that includes \( H \) as a subset.
Subgroup
A subgroup is a subset of a group that is itself a group under the operation defined on the larger set. For instance, in the quaternion group \( Q_8 \), the set \( \langle j \rangle = \{ 1, j, -1, -j \} \) is a subgroup generated by the element \( j \).
- Any subgroup must satisfy the group properties: closure, associativity, identity, and inverses.
- Subgroups often reveal important structural aspects of the larger group they are part of.