Chapter 8: Problem 8
Find (a) The domain. (b) The range. $$ y=\sqrt{x}+1 $$
Short Answer
Expert verified
Answer: (a) Domain: \(x \geq 0\); (b) Range: \(y \geq 1\)
Step by step solution
01
Analyze the function
The given function is of the form \(y = \sqrt{x} + 1\). This function is a transformation of the basic square root function \(y = \sqrt{x}\), where 1 is added to the square root part.
02
Determine the domain of the original square root function
Recall that the square root of a number can only be found if the number inside the square root is greater than or equal to 0. Therefore, for the function \(y = \sqrt{x}\), the domain is all non-negative real numbers. In inequality form, the domain can be represented as:
\[x \geq 0\]
03
Determine the domain of the transformed function
Adding a constant term to the square root function does not affect its domain. The constant only affects the y-values, not the x-values. Therefore, the domain of the function \(y = \sqrt{x} + 1\) is the same as that of the original square root function, which is all non-negative real numbers or in inequality form:
\[x \geq 0\]
04
Determine the range of the original square root function
For the original square root function \(y = \sqrt{x}\), the output value, y, will always be greater than or equal to 0 since the square root of a non-negative value is non-negative. In inequality form, the range can be represented as:
\[y \geq 0\]
05
Determine the range of the transformed function
In the transformed function \(y = \sqrt{x} + 1\), the constant term, 1, is added to the square root part. Thus, the minimum value of y is now 1. For a range, it can be described in inequality form as:
\[y \geq 1\]
06
Final Answer
Based on the steps above, the domain and range of the given function are as follows:
(a) Domain: \(x \geq 0\)
(b) Range: \(y \geq 1\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Root Function
The square root function is a basic and essential mathematical function often represented by the formula \(y = \sqrt{x}\). The primary goal of this function is to find the non-negative root of a given non-negative number. In simpler terms, it's the positive number that, when squared, gives you the original value under the square root.
- For example, when \(x = 4\), \(y = \sqrt{4} = 2\).
- It's important to note that the square root function is only defined for values of \(x\) that are zero or greater. This is because the square root of a negative number isn't a real number.
- Therefore, the domain of the square root function is always \(x \geq 0\).
Transformation of Functions
Transformations allow us to change basic functions into newer, often more complex, variations. When we look at \(y = \sqrt{x} + 1\), we're applying a transformation to the square root function. But how?
- Here, we added a constant 1 to the basic function \(y = \sqrt{x}\).
- This operation is known as vertical translation or shift.
- Adding 1 moves the entire graph of \(y = \sqrt{x}\) up by 1 unit on the y-axis.
Inequality Representation
Inequality representation is a critical part of understanding and expressing the domain and range of functions. When working with functions like \(y = \sqrt{x} + 1\), representing conditions such as domain and range effectively is essential for clarity.
- The domain, here represented as \(x \geq 0\), signifies that all values of \(x\) are zero or positive. It's due to the fact that you can't take the square root of a negative number in real numbers.
- The range, written as \(y \geq 1\), indicates that the lowest possible output of our transformed function is 1, owing to the addition of the constant 1 to the square root value.